Three Conditions Leading to a Unified (Quasi-Newtonian) Physics
ABSTRACT
It is shown that the total escape speed u (i.e. from all the masses in space), which depends on the total gravitational potential U through the relation u = (&minus;2U)1/2, tends to c; then, under the 1st condition c = u, and assuming (as a 2nd condition) the light as composed of longitudinally-extended, elastic (i.e. variable length) and massive particles, (photons), emitted at speed u referred to the initial location (O) of their source, we show that c referred to O becomes invariant despite any motion of its source from O. We revised the Doppler effect for the light, the gravitational redshift cause, the time dilation, highlighting the differences with respect to the Relativity. In the 2nd part, considering (3rd condition) the electron charge as a point-particle fixed to the electron surface and facing the atom nucleus during the electron orbit, the light-matter interaction becomes a consequence of the particular impacts between these photons and the circling electrons: e.g., on H atom, we found 137 circular orbits only, the last one being the ionization orbit, where the electron orbital speed becomes v i= c/1372. [Classical physics, under the assumption that a circling electron should produce (like a macroscopic electric circuit), an electro-magnetic radiation, implies that this claimed effect has to cause the electron fall into its nucleus: on Section 2.5, we show that the e.m. radiation of a circling electron only happens between two circular orbits].

1. Speed of Light

1.1. Introduction

This paper is based on the following assumptions:

1) Finite mass of the universe.

2) Newton’s absolute time and space.

Then, the following two conditions:

− Equality between the speed of light c and the total escape speed u.

− Light composed of longitudinal-extended, elastic particles, as defined on Section 1.4.

We obtain, on the 1st Part, these main results:

1) The measured constancy of c is due, first, to the constancy of the total gravitational potential U on Earth: indeed, the max variation of U on Earth, occurring between Aphelion and Perihelion, leads to a negligible ΔuAP = 0.10 m∙s-1; moreover, the speed of light emitted by a source, either fixed or in motion from its initial location O (where the photons emission starts), is invariant with respect to O;

2) Doppler effect equations for the light, slightly different from the relativistic ones;

3) The compensating velocity, (to restore the resonance source-absorber on Harvard Tower Experiment), has same value but contrary direction with respect to the one predicted by GR;

4) The variation of U from ground to GPS satellite level, implying a decrease of c and consequently a decrease of the frequency of the photons emitted by atomic clocks at that altitude, give them an increase of their counted time (inducing them to run faster);

5) High gravitational redshifts are due to the increase of c (inducing the increase of the photons length λ) during their path toward the Earth where |Uo| >> |U→∞|.

On the 2nd part, under the third condition claiming that the electron charge can be considered as a point-particle fixed to the electron surface, and facing the atom nucleus during the electron orbit, we got these results:

On H atom:

6) n = 1, 2, ∙∙∙, 137 electron circular progressive orbits, not an infinite number; n also represents the number of admitted photons (of the same ray) absorbed (or emitted) by the electron during two electron orbits: (in fact, the photons total number along each circular double-orbit (in short d-orbit) becomes n2, as shown on Section 2.4);

7) The electron radius becomes ${r}_{\text{e}}=\left[\left(1/137\alpha \right)-1\right]{r}_{0}$ (instead of its classical value re = α2rB with ${r}_{\text{B}}=\alpha /4\pi {R}_{\infty }$ the Bohr radius and α the fine structure constant); ${r}_{0}=\alpha /4\pi {R}_{\text{H}}$ is the orbit of the electron charge, while the orbit of the electron barycenter (electron effective orbit) becomes ${{r}^{\prime }}_{0}={r}_{0}+{r}_{\text{e}}={r}_{0}/137\alpha$ ;

8) The electron charge orbital speed along r0 becomes ${\upsilon }_{0}=\alpha c$ , while the electron effective orbital speed along the orbit ${{r}^{\prime }}_{0}$ becomes ${{\upsilon }^{\prime }}_{0}=c/137$ ;

9) The electron radial speed (due to the impacts photons-electron) becomes ${w}_{{n}^{2}}$ = c/1372 constant for every circular orbit; along the orbit #137, the electron orbital speed becomes ${\upsilon }_{137}={c/137}^{2}$ and since ${w}_{{n}^{2}}={\upsilon }_{137}$ there is ionization.

10) On Photoelectric effect the number of photons hitting a circling electron varies from nf related to the specific threshold frequency nf (=Wf/h) to (nf)½ related to a higher frequency corresponding to the lower frequency occurring for the Compton effect; for instance, it is shown that, as for Caesium (having Wf @ 2 eV), nf = 361;

11) Compton effect (CE) needs one photon only; our Doppler effect equations for the light lead to Compton Eq., while, as for the Relativity, the CE is not a Doppler effect.

1.2. Total Escape Speed u and Evidences That u = c

As known, considering in space only one mass M, (for simplicity its barycenter), the gravitational potential U in a point O, assuming U¥ = 0, is U = −MG/s, with s the distance M-O. The conservation of energy applied to a particle m (of unitary mass) coming from the infinity, gives E = U + K, with K = ½u2 its kinetic energy, therefore for E = 0, one finds U = −K, yielding

$u=\sqrt{-2U}=\sqrt{2MG/s}$ (1)

which is a scalar, (called escape speed), representing the value of the velocity u, (referred to M), a massive particle needs to reach the infinity; hence the relation

${v}_{\text{Mm}}=u$ [with $|u|=u={\left(-2U\right)}^{1}{2}}$ ] (2)

represents the condition, as for a point-particle m, to be provided with the absolute escape velocity u (absolute means here referred to M) whereas considering a generic point O,

${v}_{\text{Om}}\equiv {u}_{\text{O}}$ [with $|{u}_{\text{O}}|={u}_{\text{O}}={\left(-2{U}_{\text{O}}\right)}^{1}{2}}$ ] (3)

represents the condition, regarding m, to be provided with the relative escape velocity uO, where relative means here referred to a generic point O; (anyhow, our claimed variable length of photons, during their emission from a source S gives them an invariant speed referred to any considered point O, in spite of any velocity vOS).

Regarding the possibility to define the escape speed from two or more masses, we point out that considering M as a real mass, the potential U, in a considered point, has to be regarded as the sum of the partial potentials Un due to each partial mass Mn composing the mass M; therefore, as for two masses, we have

${U}_{1,2}\equiv {U}_{1}+{U}_{2}=-\left({M}_{1}G/{s}_{1}\right)-\left({M}_{2}G/{s}_{2}\right)$ (4)

yielding ${u}_{1,2}\equiv \sqrt{-2{U}_{1,2}}=\sqrt{-2\left({U}_{1}+{U}_{2}\right)}$ thus we can write

${u}_{1,2}^{2}=-2{U}_{1,2}={u}_{1}^{2}+{u}_{2}^{2}$ (5)

while for all the n masses in space we get

$u\equiv {\left(-2U\right)}^{½}={\left(-2\Sigma {U}_{n}\right)}^{½}={\left(2\Sigma {M}_{n}G/{s}_{n}\right)}^{½}=\sqrt{\Sigma {u}_{n}^{2}}$ (6)

representing the total escape speed.

For instance, the escape speed from the Earth surface, due to Earth and Sun only, becomes ${u}_{\text{E},\text{S}}^{2}={u}_{\text{E}}^{2}+{u}_{\text{S}}^{2}=\left(\text{2}{M}_{\text{E}}G/{R}_{\text{E}}\right)+\left(\text{2}{M}_{\text{S}}G/d\right)$ with RE the Earth radius, and d the distance Earth-Sun giving uE,S $\cong$ 42 km/s, while the escape speed from our Galaxy can be roughly expressed as ug ≃ (2MgG/dg)½ where Mg ≃ 1042 kg is our Galaxy mass and dg ≃ 30 kly ≃ 3 ´ 1020 m the distance between the Earth and our Galaxy centre, giving ug ≃ 8 ´ 105 m∙s-1.

Now, the mass of universe, by some authors, is estimated    to be Mu $\cong$ 1053 kg; about the same value is given through the number ( $\cong$ 1022) of observable stars    , and since from Earth the distribution of the masses appears to be homogeneous and isotropic, under our assumption U¥ = 0, we may assume their density as decreasing toward the infinity like a function ρ = ρceas being ρc $\cong$ 9.2 ´ 10−27 kg/m3 the critical density.

Writing the mass of universe as

${M}_{\text{u}}={\int }_{0}^{\infty }4\pi {s}^{2}{\rho }_{c}{\text{e}}^{-as}\text{d}s=4\pi {\rho }_{c}{\int }_{0}^{\infty }{s}^{2}{\text{e}}^{-as}\text{d}s=\frac{8\pi {\rho }_{c}}{{a}^{3}}\cong {10}^{53}\text{kg}$ (7)

we find

$a={\left(8\pi {\rho }_{c}/{M}_{\text{u}}\right)}^{\frac{1}{3}}\cong 1.3×{10}^{-26}{\text{m}}^{-1}$ (8)

and since, on Earth, the variation of potential due to an increase of the distance ds, can be written dU = −dm G/s with dm = ρ4πs2ds and ρ = ρceas, the potential on Earth becomes

$\begin{array}{c}{U}_{0}=-{\int }_{0}^{\infty }\left(4\pi {s}^{2}/s\right)G{\rho }_{c}{\text{e}}^{-as}\text{d}s=-4\pi {\rho }_{c}G{\int }_{0}^{\infty }{\text{e}}^{-as}s\text{d}s\\ =-4\pi {\rho }_{c}G/{a}^{2}\cong -4.5×{10}^{16}\text{J}\end{array}$ (9)

yielding

${u}_{0}={\left(-2{U}_{0}\right)}^{½}\cong {\left(9×{10}^{16}\right)}^{½}\cong 3×{10}^{8}\text{m}/\text{s}.$ (10)

We can therefore infer that, on Earth, u0 = c0, giving ${c}_{0}^{2}/2=-{U}_{0}$ and, in general,

$c={\left(-2U\right)}^{½}=u.$ (11)

The equality c = u, which implies the massiveness of light, means that, along any free path, the speed of light only depends on the value of the potential along that path.

The equality c = u is also supported by a cosmological reason: in fact, if c > u the energy of light will be lost forever and furthermore the observable masses, following the always increasing mass of light going toward the infinity, will also tend to the infinity moving away from each other. On the contrary, if c < u, all the masses in space, (having speed lower than u), will tend to a gravitational collapse, whereas for c = u, the mass of light, tending to the infinity in an unlimited time, appears to be the necessary mass to avoid the two events (collapse or dispersion).

1.3. Annual Variation, on Earth, of the Total Escape Speed

On Earth, a small variation of the total escape speed uo, from Equation (11) written as u2 = −2U yielding 2u = −2dU/du, can be written as

$\text{Δ}u=-\text{Δ}U/{u}_{0}$ (12)

where ΔU is the variation of the total potential on Earth, mainly due to the variable distance Earth-Sun; so, between Aphelion and Perihelion, where a = (1 + e)d and p = (1 − e)d are the respective distances Earth-Sun, with e (=0.0167) the eccentricity of the Earth’s orbit and d $\cong$ 1.5 ´ 1011 m the average distance Earth-Sun, and since pa $\cong$ d2, and (a - p) = 2ed, we get

(13)

with MS = 2 ´ 1030 kg the mass of the Sun, and we note that ΔuAP is compatible with the accuracy of the value of the speed of light in vacuum (on Earth) c0 = 299,792,458 m∙s−1.

1.4. Definition of Photons and Their Speed

The Galileo’s velocity composition law (since different parts of a moving object may have different velocity) is strictly valid for point-particles, and therefore the light cannot be a succession of point-particles (otherwise it should follow this Galileo’s law), hence we may infer that the light, to comply both this law and the equality c = u, could be composed of particular particles, photons, (whose physical characteristics are then shown on §2.2), as defined:

Longitudinally-extended, elastic (variable length) and massive particles emitted by a source during an emission time T at speed c = u moving individually or along rays, (continuous succession of photons where every tail corresponds to the front of the next one).

Photons speed: the measurement of the speed of a point-particle (or regarding an object, its barycentre), is defined through the ratio v = d/t with d the distance between two Observers (O1 and O2) and t (=t2 - t1) the time the particle/barycentre needs to cover such a distance; on the contrary, every photon may have different length with respect to two Observers, (like, for instance, an elastic thread during its stretching), hence to define the speed of one photon, we must consider its length λ divided its transit time Tt (time the whole particle needs to cross one Observer). Therefore the relation

$c=\lambda /{T}_{t}$ (14)

represents the speed of one photon referred to a considered Observer, whereas the relation c = d/t, written as

$c=d/t=n\lambda /n{T}_{t}=\lambda /{T}_{t}$ (14-a)

where n is the number of photons (of one ray) each of them having length λ, and where t = nTt is the transit time of the n photons, represents the average speed of the light along d.

1.5. Invariance of c for Observers at Rest with Respect to the Initial Location O of a Source of Light, Despite Any Velocity vOS

Referring to Figure 1, let O be the location (with respect to all the masses in

Figure 1. Emission of the photon AB by a source S either at rest or in motion from O.

space) of the source S at the time (t = 0) the front A is emitted; therefore O represents the location of the initial emission of a considered photon.

The Earth’s surface, where c0 is practically constant, has to be intended as the basic reference frame for the parameters of light (λ, ν) while other frames, because of the Doppler effect, would give, for the same source, different values. So, still referring to Figure 1, we intend the frame O as fixed to the Earth’s surface. We also intend:

T: emission time of the considered photon AB.

λ: length of the emitting photon if S is fixed to O during T.

λO: length of an emitting photon if S during T is in motion with respect to O.

Tt : transit time of one photon (TO for O, TP for P, while TS = T ).

On Figure 1, if S during T is fixed to O, the speed of the front A (considered as a point-particle), see Equation (3), is υOA = uO, where uO only depends on the location of O, thus, at t = T, the length λ of the photon AB corresponds to the path covered by A, so we have

${\upsilon }_{\text{OA}}T={u}_{\text{O}}T\equiv$ (= ${\upsilon }_{\text{SA}}T$ for S fixed to O during T). (15)

If S has velocity vOS with respect to O, the velocity of the front A, referred to S, being vSA = vSO + vOA and since from (3), vOA = uO, becomes

${v}_{\text{SA}}={v}_{\text{SO}}+{u}_{\text{O}}⇒{\upsilon }_{\text{SA}}={u}_{\text{O}}±{\upsilon }_{\text{OS}}$ (16)

with the sign + if photon and source have opposite direction; then

${\upsilon }_{\text{SA}}T\left(\equiv {\lambda }_{\text{O}}\right)={u}_{\text{O}}T±{\upsilon }_{\text{OS}}T⇒{\lambda }_{\text{O}}=\lambda \left(1±\beta \right)$ [with $\beta ={\upsilon }_{\text{OS}}/{u}_{\text{O}}$ ] (17)

where λO is the length of the emitted photons when S is in motion from O. We point out that the variation of the photons length only depends on ${v}_{\text{OS}}$ .

Now, the transit time Tt for the Observer O, can be written

${T}_{\text{O}}=T±{\upsilon }_{\text{OS}}T/{u}_{\text{O}}=T\left(1±\beta \right)$ [with $\beta ={\upsilon }_{\text{OS}}/{u}_{\text{O}}$ ] (18)

corresponding to the algebraic sum of the time T (=λ/uO) the front A needs to cover the path λ, plus the time the tail B (emitted, like every part of the photon, at speed uO referred to O), needs to cover the path ST - O = υOST, that is ΔT = υOST/uO. (As for the observer P showed on Figure 1, being vOP = 0, then TP = TO).

Thus, the speed of the photon AB referred to O, since TO increases/decreases together with λO, as per Equation (14), becomes

${u}_{\text{O}}=\frac{{\lambda }_{\text{O}}}{{T}_{\text{O}}}=\frac{\lambda \left(1±\beta \right)}{T\left(1±\beta \right)}=\frac{\lambda }{T}\equiv c$ (19)

showing that the speed of a photon referred to an Observer fixed to the source initial location, (O), is invariant despite any motion of the source with respect to O.

The frequency of the light referred to a generic Observer O, on our bases, has to be defined as ν = n/Tt with n the number of photons, of the same ray, crossing the Observer during their transit time Tt . Hence, for Tt = 1 s, we have ν = n meaning that the frequency corresponds to the number of photons, same ray, transiting in 1 s, while, for n = 1, the frequency becomes

$\nu =1/{T}_{t}$ (20)

We point out that the photons frequency emitted by a source S, under the condition υOS = 0, has to be equal to the one observed by O; this is also valid if O and S belong to different potential, (e.g., the equality of the number of balls falling from the top of a tower with respect to an Observer at the tower base), and therefore the condition υOS = 0 always implies nS = nO whatever is the distance source-observer.

[We also point out that, according to the Relativity, (due to the claimed constancy of c and because of the Doppler effect), an Observer in relative motion from a source should observe different wavelength as well as different frequency for emitted light; on the contrary, on our results, if the source is fixed to its initial location (the ground on Earth), the length of the emitted photons is invariant, while c and ν are varying, as hereafter shown].

Referring now to Figure 2, let P be an observer (represented at different times, by PA and PB) moving with velocity vOP from O along the same direction of the photons while the source S is moving from O with velocity vOS contrary to them; we assume the photon AB totally emitted at the time the front A reaches PA (for simplicity as t = 0). [In fact, after this emssion, the source may even disappear].

Now, the transit time TP of the photon AB is given, see Equation (18), by TO plus the time TOP (= $±{\upsilon }_{\text{OP}}T/c$ ) due to the motion of P from O, and since vSP = vSO + vOP, we can write

${T}_{\text{p}}=T±\frac{{\upsilon }_{\text{SO}}T}{c}±\frac{{\upsilon }_{\text{OP}}T}{c}\left(=T±\frac{{\upsilon }_{\text{SP}}T}{c}\right)=T\left(1±\beta ±{\beta }_{\text{P}}\right),\text{\hspace{0.17em}}\text{\hspace{0.17em}}\left[\text{with}\text{\hspace{0.17em}}{\beta }_{\text{p}}=±\frac{{\upsilon }_{\text{OP}}}{c}\right]$ (21)

Figure 2. The Observer P moves from PA to PB during the transit time TP of the photon AB while the source is moving from its initial emission location O.

corresponding to the interval between the time the front A reaches PA (at t = 0) and the time the tail B leaves PB; hence

${c}_{\text{p}}={\lambda }_{\text{O}}/{T}_{\text{p}}=\lambda \left(1±\beta \right)/T\left(1±\beta ±{\beta }_{\text{p}}\right)=c\left(1±\beta \right)/\left(1±\beta ±{\beta }_{\text{p}}\right).$ (22)

[In short, the motion of S (from O) causes a variation of the photon length, while the relative motion observer-source varies the observer transit time and its related frequency].

On next Figure 3, we analyse the parameters c, λ, ν of five configurations regarding a source S, the considered frame O (practically the Earth’s surface) and an Observer P.

Figure 3. Five configurations regarding a source S, a frame O and an Observer P.

where

β = υOS/c, relative speed of S with respect to O,

βp = υOP/c relative speed of P,

c = λ/T basic speed of light, referred to conf. #1,

λO = λ(1 ± β) length of emitted photon,

TS = T photon transit time for S, equal to its emission time,

TO = T(1 ± β); Tt for O; sign + if S and photon have opposite direction,

TP = T(1 ± β ± βp); Tt for P; +βp if P and photon have same direction,

cS = λO/TS = λO/T; speed of light observed by S,

cP = λO/TP speed of light observed by P,

cO = λO/TO speed of light observed by O.

Regarding the measurements of c through the method c = d/t carried out along a double path, the light emitted inside the measurement system (MS), because of the interaction light-matter, has to be absorbed and then re-emitted by the 2nd Observer which, during the re-emission, becomes a new emitting source; therefore the above equations regarding transit time and photon length, are also valid for the re-emitted photons which now have contrary direction, hence β' = −β and also λ' = −λO giving to c, along a double path, the constant value c.

[Light emitted outside the MS: at the time the light is crossing the MS, this becomes the new emitting source].

1.6. Doppler Effect for the Light, New Equations

The Equation (17) represents our longitudinal Doppler effect for the light, while the general case of this effect, assuming υOS << λ (hence OP ≅ PB), see Figure 4(a), can be written as

${\lambda }_{0}=\lambda ±{\upsilon }_{\text{OS}}T\mathrm{cos}\alpha =\lambda \left(1±\beta \mathrm{cos}\alpha \right)$ (with $\beta ={\upsilon }_{\text{OS}}/c$ ) (23)

with α the angle between the direction of λO and vOS.

As for the Transverse Doppler effect, see Figure 4(b), in general, we have

${\lambda }_{0}=\sqrt{{\lambda }^{2}±{\left({\upsilon }_{\text{OS}}T\right)}^{2}}=\lambda \sqrt{1±{\beta }^{2}}$ (24)

Figure 4. Doppler effect (DE). (a) General case; (b) Transverse DE with S receding/ap- proaching an observer P. Dotted arrows inside the triangles represent the photon λO during its emission.

As for a source circling around an Observer P, the Figure 5 shows that the length of the photon λ emitted when its source is fixed to O, becomes λO when S is circling with velocity vOS.

Figure 5. Photons emitted while their source is circling around P.

[The succession of the photons λ represents a ray if S is at rest with P, while the succession λ1 ® λ3 represents a ray if S is circling around P, with O, B, C the emission points of the circling source]. Then, assuming λO > λ, we have

${\lambda }_{\text{O}}=\sqrt{{\lambda }^{2}+{\left({\upsilon }_{\text{OS}}T\right)}^{2}}=\lambda \sqrt{1+{\beta }^{2}}=\lambda \sqrt{1+{\omega }^{2}{r}^{2}/{c}^{2}}$ (25)

while the photon transit time, being T the emission time of λ becomes

${T}_{\text{O}}=T\sqrt{1+{\beta }^{2}}=T\sqrt{1+{\omega }^{2}{r}^{2}/{c}^{2}}$ (26)

with r the orbit radius, ω the source angular speed, giving to any photon, speed cO = c.

1.7. Re-Visitation of the Harvard Tower Experiment (HTE), Time Dilation, Gravitational Redshift

General Relativity predicts that the gravitational field of the Earth will cause a photon emitted downwards (towards the Earth) to be blueshifted: scope of HTE experiment was to detect this shift of light. A Mossbauer source S was placed on the top of a tower (height h @ 22 m) emitting photons toward the tower base where an Absorber went out of resonance; the experiment did not clarify if the non-resonance was due to a variation of λ or ν; indeed, because of the claimed constancy of c, both of them should have varied their initial values during the path tower-base.

According to our bases, we have different evaluations of this experiment. Let us first consider S at the base and A at its top, see Figure 6.

It is a fact that if S and A are at relative rest at the same level (e.g. both on the ground), then A is in resonance and it is also a fact that other experiments effected at this regard, e.g. Blatt,  , show that if S moves toward the absorber, not contrarily, the absorber goes out of resonance: indeed, if S is fixed to the ground, the length of emitted photons (as previously shown) is constant, whereas if S moves with respect to its initial emission location (the ground), the photon length varies, thus we may infer that the resonance is physically related to the constancy of the length of photons.

Figure 6. Harvard tower experiment scheme; source at the base, absorber A at the top, our results. (a) S and A at rest, so νh = n0; c0, ν0, λ0 parameters of photons emitted by S on the ground; ch, nh, λh photons arrived to A where λh < λ0 thus a blue shift as for A; (b) Direction of the compensating velocity to balance the blue shift via Doppler effect, so to obtain in altitude c0, n0, λ0.

Now, referring to Figure 6, if S, on the ground, emits photons reaching A at height h, because of the variation of potential, following our relation c = (−2U)½, it will be c0 ® ch; since S and A are at reciprocal rest, it turns out that, as shown just after the Equation (20), it is always νh = ν0 (in spite of any variation of potential between S and A) yielding λh = chh. Therefore, with r0 the radius of Earth (hence rh = r0 + h) and ME the mass of Earth, writing the (11) as c2 = −2U, we get 2c = −2dU/dc hence from r0 to rh and since Δc = −ΔU/c with ΔU = UEh - UE0 = − (MEG/rh) + MEG/r0, we find

$\frac{{c}_{h}-{c}_{0}}{{c}_{0}}=-\frac{\text{Δ}U}{{c}_{0}^{2}}=-\frac{{M}_{E}Gh}{{r}_{h}{r}_{0}{c}_{0}^{2}}\cong -gh/{c}_{0}^{2}⇒{c}_{h}={c}_{0}\left(1-gh/{c}_{0}^{2}\right)$ (27)

(where ΔU = gh); then for nh = n0 we have

$\begin{array}{l}{\lambda }_{h}={c}_{h}/{\nu }_{h}={c}_{0}\left(1-gh/{c}_{0}^{2}\right)/{\nu }_{0}={\lambda }_{0}\left(1-gh/{c}_{0}^{2}\right)\\ ⇒\left({\lambda }_{h}-{\lambda }_{0}\right)/{\lambda }_{0}=-gh/{c}_{0}^{2}=\frac{{c}_{h}-{c}_{0}}{{c}_{0}}\end{array}$ (28)

and since λh < λ0, contrary to Relativity, A observes a blue-shift effect.

Thus, to restore the resonance via Doppler Effect (DE), see Figure 6(b), S has to recede from A in order that the photon length could increase, see Equation (17), from λh to ${\lambda }_{0}={\lambda }_{h}\left(1+\beta \right)$ with $\beta ={\upsilon }_{\text{AS}}/c\equiv \upsilon /c$ ; therefore, equating the relative variation of the photon length due to the DE, that is (λh − λ0)/λ0 = −υ/c, to the one due to the altitude, Δλ/λ0, as given by (28), we get

$\upsilon /c=gh/{c}_{0}^{2}⇒\upsilon =gh/{c}_{0}=7.5×{10}^{-7}\text{m}/\text{s}$ (for h = 22.5 m) (29)

i.e. the value of the compensating velocity.

This value is also predicted by GR which, implying a decrease of ν for the light moving from the base to the top, predicts an opposite direction of the compensating velocity v with respect to the one shown on Figure 6(b); at this regard, Pound-Rebka and Pound-Snider,    , gave no clear indication about the direction of v, since S and A, during the experiment, were moved sinusoidally.

Now, see Figure 7, with A on the base, and taking S to the top, the experience

Figure 7. Harvard tower experiment scheme; source on the top, our results.

shows that the absorber goes out of resonance. Indeed, with S on the top, the (27) shows ch < c0, but what about the initial parameters of the photons emitted in altitude, nh and λh?

Well, it is known that atomic clocks give an increase of their counted time in altitude (Th > T0, hence νh < ν0), therefore taking these clocks from ground to h, their frequency nh has to follow the same decrease as ch; this implies λh = λ0 so the frequency of photons emitted in altitude becomes

${\nu }_{h}=\frac{{c}_{h}}{{\lambda }_{h}}=\frac{{c}_{0}\left(1-\frac{gh}{{c}_{0}^{2}}\right)}{{\lambda }_{0}}={\nu }_{0}\left(1-\frac{gh}{{c}_{0}^{2}}\right)={\nu }_{0}\left(1-\text{Δ}U/{c}_{0}^{2}\right).$ (30)

Now, with S emitting photons toward the base, since S and A are at rest, their frequency remains constant during their path top-base, meaning that ${\nu }_{h-0}={\nu }_{0}\left(1-\text{Δ}U/{c}_{0}^{2}\right)$ , while the length of photons reaching the base, and considering that now h is negative, becomes

${\lambda }_{h-0}={c}_{0}/{\nu }_{h-0}={c}_{0}/{\nu }_{0}\left(1-\text{Δ}U/{c}_{0}^{2}\right)={\lambda }_{0}\left(1+gh/{c}_{0}^{2}\right)$ (31)

showing an increase of λ from the top to the base. Hence the absorber, on the base, will state, contrary to GR, a red-shift, hence, to compensate it via Doppler shift, see Figure 7, S has now to move toward A; on the contrary, according to GR, A and S should recede from each other. We also highlight two points:

− The increase of λ for photons moving from h to the ground, gives a reason to the gravitational red shift related to far sources.

− The decrease of ν during the path h-ground gives a reason to the lower frequency of the light coming from far sources.

Time dilation: Atomic clocks in altitude (h-clocks) are ticking faster than identical clocks on the ground (g-clocks): at height h, see (27), we have $\left({c}_{h}-{c}_{0}\right)/{c}_{0}=-\Delta U/{c}_{0}^{2}$ , while taking a clock to a GPS satellite, see also Figure 7(a), from (30), one finds

${T}_{h}={T}_{0}/\left(1-\frac{\Delta U}{{c}_{0}^{2}}\right)={T}_{0}/\left(1-\delta \right)⇒{T}_{h}-\delta {T}_{h}={T}_{0}$ [where $\frac{\text{Δ}U}{{c}_{0}^{2}}\equiv \delta$ ] (32)

with Th the counted time of one photon emitted by a h-clock, while T0 by a g-clock. Thus the variation of the counted time between the two clocks, for every emitted photon, due to the altitude, becomes

$\text{Δ}{T}_{\text{ph}}={T}_{h}-{T}_{0}={T}_{h}\delta$ (33)

and since the frequency of photons is their number emitted in 1 s along one ray, the term

${n}_{1\text{s}}\equiv {\nu }_{0}{t}_{1\text{s}}$ (with ${t}_{1\text{s}}=1\text{\hspace{0.17em}}\text{s}$ ) (34)

is the number of photons (atomic transition of Cs 137) constituting one-second on the ground; then, since ${\nu }_{h}={\nu }_{0}\left(1-\text{Δ}U/{c}_{0}^{2}\right)$ , see (30), the following relation

$\Delta {n}_{1\text{s}}={\nu }_{h}\Delta {T}_{\text{ph}}=\frac{{\nu }_{0}\left(1-\frac{\Delta U}{{c}_{0}^{2}}\right)\left({T}_{0}\frac{\Delta U}{{c}_{0}^{2}}\right)}{1-\frac{\Delta U}{{c}_{0}^{2}}}={\nu }_{0}{T}_{0}\frac{\Delta U}{{c}_{0}^{2}}=\frac{\Delta U}{{c}_{0}^{2}}$ (35)

is the variation of ${n}_{1\text{s}}$ emitted in 1 s by a h-clock; now, see (27), ΔU = MEGh/rhr0 and since rh ≅ 26,600 km , r0 ≅ 6400 km, with h ≅ 20,200 km , the increase of counted time in one day ( $\Delta {T}_{1d}$ ) of a h-clock, with respect to a g-clock, becomes

$\Delta {T}_{1\text{d}}=\Delta {n}_{1\text{s}}×86400\text{\hspace{0.17em}}\text{s}=86400\Delta U/{c}_{0}^{2}=45.5\text{\hspace{0.17em}}\text{μs}$ (36)

hence this effect is a consequence of the variation of U; indeed, as shown later on, the values of the H atom frequencies depend on c, thus, on our bases, on U.

Now let us find the variation of the counted time, between the two clocks, due to their relative motion; thus, being vS = 2 (2πrh/86,400 = 3870 m/s the orbital speed of GPS satellites, (corresponding to two orbits/day), it turns out that the counted time variation, between a h-clock and an Observer E at the centre of Earth, due to their relative motion, is given by Equation (26) which, in our case, with βS = vS/c (≅1.3 × 105) becomes

${T}_{\text{E}}={T}_{h}\sqrt{1+{\beta }_{\text{S}}^{2}}\cong {T}_{h}\left(1+\frac{{\beta }_{\text{s}}^{2}}{2}\right)$ (valid for ${\beta }_{\text{S}}^{2}$ << 1) (37)

with TE the photon counted time for the Observer E; then, with v0 the Earth’s rotational speed (@ 460 m/s at the equator), since ${\beta }_{0}^{2}$ = (v0/c)2 << ${\beta }_{\text{S}}^{2}$ = (vS/c)2 and calling ${T}_{0}\cong {T}_{h}\left(\text{1}+{\beta }_{0}^{2}\right)$ the photon counted time of a g-clock with respect to a clock at the Earth’s centre E, we can write T0 ≅ TE; thus, the difference between the two transit times Th and T0 (≅ TE) due to their relative motion, is

$\Delta {{T}^{\prime }}_{\text{ph}}={T}_{h}-{T}_{0}\cong {T}_{h}-{T}_{\text{E}}={T}_{h}-{T}_{h}\left(1+\frac{{\beta }_{\text{s}}^{2}}{2}\right)=-{T}_{h}{\beta }_{\text{S}}^{2}/2$ . (38)

Then, as above, $\text{Δ}{{n}^{\prime }}_{1\text{s}}\equiv {\nu }_{h}\Delta {{T}^{\prime }}_{\text{ph}}=-{\nu }_{h}{T}_{h}{\beta }_{\text{S}}^{2}/2=-{\beta }_{\text{S}}^{2}/2$ is the variation of the number of photons emitted by a h-clock in 1 s; so the variation of the counted time, in one day, is

$\text{Δ}{{T}^{\prime }}_{1\text{d}}=-\left(\frac{{\beta }_{\text{S}}^{2}}{2}\right)86400\text{\hspace{0.17em}}\text{s}=-7.2\text{\hspace{0.17em}}\text{μs}$ (39)

showing a decrease of the counted time for a g-clock due to their relative motion; hence

$\text{Δ}{T}_{\text{tot}1\text{d}}=\text{Δ}{T}_{1\text{d}}+\text{Δ}{{T}^{\prime }}_{1\text{d}}=38.3\text{\hspace{0.17em}}\text{μs}/\text{day}$ (40)

which is also predicted, (with different reason), by GR. To prevent this effect, before launching, the daily counted time (T1d) of clocks, has to be decreased by ≅38 μs.

In short, the time dilation is a consequence of the variation of U, hence of c: indeed, as show on §2.3, the admitted/emitted frequency on H atom (and of course the one of the other elements) varies together with c.

Gravitational redshift

As for the Relativity, the only way to explain high cosmological redshifts is the Doppler effect, (which implies an incredible universe expansion at a speed υu ≅ c), whereas, on our results, disregarding the reciprocal motion between a (far) source and an Observer on Earth, which implies ν = ν0, we get c/λ = c00, where ν0, c0 and λ0 are the values on Earth, hence for c0 > c one gets λ0 > λ, that is a red shift observed on Earth; therefore, the shifts here observed can be expressed as

$z\equiv \frac{\Delta \lambda }{\lambda }=\frac{\Delta c}{c}=\frac{{c}_{0}-c}{c}=\frac{{c}_{0}}{c}-1=\sqrt{{U}_{0}/U}-1$ (41)

with U0 the potential on Earth, U the one on the source. Thus, apart from Doppler effects, z turns out to be the variation of c (as well as λ) during the path of light toward a different potential. In particular, with s the distance Earth-source, for s < @45 Mpc,  , (roughly corresponding to −0.01 < z < +0.01) if U (potential on the source) is, in absolute value, higher than the potential on Earth U0, the (41) gives, on Earth, z < 0 (blue shift), and vice versa for |U| < |U0|; thus, for s < @45 Mpc, these red/blue shifts indicate that the potential, may increase or decrease with respect to |U0|. In the range @0.01 < z < @0.20, (where z follows the Hubble’s law), the (41), written as

$U={U}_{0}/{\left(1+z\right)}^{2}\cong {U}_{0}/\left(1+2z\right)\cong {U}_{0}\left(1-2z\right)$ (valid for z << 1) (42)

shows that, for z << 1, U depends linearly on z, as Hubble’s law; then, for s → ∞, U → 0, hence z → ∞, see Table 1.

[For s > @45 Mpc, z is always positive, hence we may infer that our galaxy is practically near/close to the middle of the masses of universe (where |U| has the max value)].

Table 1. Calculated values of U and c related to the observed shifts on earth.

2. Interaction Light-Matter

2.1. Electron Structure and Photon-Electron Impact Point

On our basis, (light composed of our photons), the interaction light-matter requires that to move a circling electron toward outer orbits, the impact photon-electron has to occur, see Figure 8(a), in a radial way, (giving origin to the radial velocity w), otherwise, other impacts could cause the electron fall into the nucleus, due, for instance, to an impact where the velocity of photons and electron have contrary direction.

To be radial, the impact must occur in a specific point, fixed to the electron surface, we call it Impact Point, which, during the electron, orbit, has to face its nucleus, (up to its removal), giving to the electron one rotation every orbit; the impacting photons have to approach the nucleus, as shown on Figure 8(b), perpendicularly to the electron orbit plane, providing, to the electron, a radial velocity w.

Moreover, we can infer that the charge of the electron, has to correspond to the Impact Point (Ip), so we may infer that each photon front is provided with a positive charge, while its tail with an equal negative one. In fact, the photon may be represented as an electric bipole.

(a) (b)

Figure 8. Photon-electron Impact point (Ip) and electron radial velocity w. (a) Electron orbit front view; (b) Side view.

2.2. Physical Characteristics of Photons

The total energy of a mass m is $E=m{c}^{2}$ also proved  by the evidence of nuclear reactions like $n+pd+\gamma$ , hence this energy has to be valid for the (massive)

light too, thus writing their energy as $E=\frac{1}{2}m{c}^{2}+\frac{1}{2}m{c}^{2}$ we have to infer that photons are provided, out of their kinetic energy ${K}_{c}=\frac{1}{2}m{c}^{2}$ with an internal

energy ${K}_{i}$ equal to ${K}_{c}$ and we point out that, toward the infinity, (where U → 0 hence c → 0), both Kc and Ki tend to 0; then, since for the light E = hν, the following relation

$E={K}_{c}+{K}_{i}=m{c}^{2}=h\nu$ (43)

has to represent the energy of one ray of light, (where photons are flowing), and where

$m=h\nu /{c}^{2}\equiv \gamma \nu$ (44)

is the mass of light, having frequency ν, passing along one ray in 1s, while the constant

$\gamma =h/{c}^{2}=m/\nu =mT=7.372495×{10}^{-51}\text{kgs}$ (45)

represents the mass of one photon crossing an observer during the transit time T, while the Planck’s constant

$h=\gamma {c}^{2}$ (46)

turns out to be the energy of one photon (mass of light of one ray passing during T).

Now, since m is the mass of light passing along one ray in 1s, the term ${n}_{\text{r}}m{c}^{2}$ , with nr the number of rays emitted by a source S, becomes the energy emitted by S in 1 s; this unitary (unit of time) energy shall be equal to the supplied power P during 1 s, yielding

${n}_{r}m{c}^{2}=P$ (47)

therefore

${m}_{\text{tot}}={n}_{r}m=P/{c}^{2}$ (48)

is the total mass lost per second by a source of light; e.g. for a 1 W lamp, we get

${m}_{\text{tot}}=P/{c}^{2}\cong 1.1×{10}^{-17}{\text{kgs}}^{-1}$ (49)

while the number nr of rays is

${n}_{r}\left(={m}_{\text{tot}}/\gamma \nu \right)=P/{c}^{2}\gamma \nu =P/h\nu$ (50)

in our case, nr ≅ 3 ´ 1018 rays, and we point out that, as for a given power P, the higher is the frequency, the lower is the number of rays, as shown by (50) written as nrν = P/h. Then, the number of photons nγ emitted in 1 s becomes

${n}_{\gamma }=\left({n}_{r}\nu \right)=P\nu /h\nu =P/h$ (51)

which, for P = 1 W, gives nγ = h−1 (=1.5 ´ 1033 photons/s), thus the inverse of Planck’s constant turns out to be the number of photons emitted in 1s by a source of unitary power, and this great number of photons allows the light to be treated as a wave.

Now, during inelastic impacts photons-electron, (like on absorption or photoelectric effetcs), both kinetic and internal energy of the light are involved, so the momentum transferred to the electron is

$p=2mc=2\gamma \nu c=2\gamma c/T$ (52)

whose validity is confirmed, see Table 2 of chapter 2.4, by the equality w137 = υ137 (with υ137 the electron orbital speed along the H atom orbit # 137 and where w137 is the value of the electron radial speed along such orbit, as a condition for the H atom ionization.

Regarding elastic impacts, the momentum transferred to the electron, is

${p}^{\prime }={m}^{\prime }c=\gamma {\nu }^{\prime }c=\gamma c/{T}^{\prime }$ (53)

either for incident or for reflectedphotons, with ${T}^{\prime }$ the total impact time for this interaction; through the (53), and also through our Doppler effect equation, see (17), we got the Compton equation (which cannot be obtained by the Relativity via their Doppler effect equations).

2.3. H Atom Parameters and Meaning of Quantum Numbers

Figure 9(a) represents, on our bases, the H atom basic configuration; on the intermediate conf. (b) the electron is represented circling along the same orbit as its charge, while on conf. (c) the electron reduced mass ${m}_{r}={m}_{\text{e}}/\left(1+{m}_{\text{e}}/{m}_{\text{P}}\right)={m}_{\text{e}}/\left(1+{\epsilon }_{m}\right)$ , with εm = me/mp, circling around the proton mass mP fixed as origin, is represented either along the effective orbit ${{r}^{\prime }}_{0}$ or along r0; referring to conf. (a) we define:

me: electron mass;

mp: proton mass;

υe = |ve| electron ground-state (orbital) speed,

υp = |vP| proton ground-state speed,

rB the ground-state orbit of the electron charge,

εr ≡ re/rB

${{r}^{\prime }}_{\text{B}}=\left({r}_{\text{B}}+{r}_{\text{e}}\right)={r}_{\text{B}}\left(1+{\epsilon }_{r}\right)$ , ground-state orbit of the electron barycentre,

rp the proton ground-state orbit.

Now, the constancy of momentum referred to conf. Figure 9(a) gives

${m}_{\text{e}}{\upsilon }_{\text{e}}={m}_{\text{p}}{\upsilon }_{\text{p}}⇒{\upsilon }_{\text{p}}={m}_{\text{e}}{\upsilon }_{\text{e}}/{m}_{\text{p}}\equiv {\epsilon }_{m}{\upsilon }_{\text{e}}$ (54)

then, equating on (a) the frequency of me and mp, we get

${\upsilon }_{\text{e}}/{{r}^{\prime }}_{\text{B}}={\upsilon }_{\text{p}}/{r}_{\text{p}}⇒{r}_{\text{p}}\left({\upsilon }_{\text{p}}/{\upsilon }_{\text{e}}\right){{r}^{\prime }}_{\text{B}}={\epsilon }_{m}{{r}^{\prime }}_{\text{B}}={\epsilon }_{m}{r}_{\text{B}}\left(1+{\epsilon }_{r}\right)$ (55)

The conf. (a), moving me (without its charge) from the orbit ${{r}^{\prime }}_{\text{B}}$ to ${r}_{\text{B}}$ (the electric forces acting on me are not involved), turns to conf. (b) where the equality between the frequency of me and the one of its charge, gives

Figure 9. H atom equivalent configurations, on our bases. (a) Observed from the electron-proton common centre of gravity B; (b) Ditto, with the electron barycentre now coincident with its proper charge; (c) Observed from the proton fixed as origin, orbited by the electron reduced mass mr represented either circling along r0 or its effective orbit ${{r}^{\prime }}_{0}$ .

${\upsilon }_{\text{e}}/{{r}^{\prime }}_{\text{B}}={v}_{\text{e}}/{r}_{\text{B}}⇒{v}_{\text{e}}={\upsilon }_{\text{e}}/\left(1+{\epsilon }_{r}\right)$ (56)

then the constancy of momentum referred to conf. (b), ${m}_{\text{e}}{v}_{\text{e}}={m}_{\text{p}}{v}_{\text{p}}$ , yields

${v}_{\text{p}}={m}_{\text{e}}{v}_{\text{e}}/{m}_{\text{p}}={\epsilon }_{m}{v}_{\text{e}}⇒{v}_{\text{p}}/{v}_{\text{e}}={\epsilon }_{m}$ (57)

then, equating on (b) the frequency of me and mp, we get

${v}_{\text{e}}/{r}_{\text{B}}={v}_{\text{p}}/{{r}^{\prime }}_{\text{p}}⇒{{r}^{\prime }}_{\text{p}}=\left({v}_{\text{p}}/{v}_{\text{e}}\right){r}_{\text{B}}={\epsilon }_{m}{r}_{\text{B}}$ (58)

and finally, see conf. (c), we find

${r}_{0}={r}_{\text{B}}+{{r}^{\prime }}_{\text{P}}={r}_{\text{B}}+{r}_{\text{B}}{\epsilon }_{m}={r}_{\text{B}}\left(1+{\epsilon }_{m}\right)={{r}^{\prime }}_{\text{B}}\left(1+{\epsilon }_{m}\right)/\left(1+{\epsilon }_{r}\right)$ (59)

where mr is circling with speed υ0 = ve + vp = ve(1 + εm); then

${{r}^{\prime }}_{0}={r}_{0}+{r}_{\text{e}}={r}_{0}+{\epsilon }_{r}{r}_{\text{B}}={r}_{0}\left[1+{\epsilon }_{r}/\left(1+{\epsilon }_{m}\right)\right]={r}_{0}\left(1+{\epsilon }_{m}+{\epsilon }_{r}\right)/\left(1+{\epsilon }_{m}\right)$ (60)

Now, it is known that, on H atom, the admitted frequencies have to satisfy the relation

${\nu }_{n}={\nu }_{0}/{n}^{2}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\text{\hspace{0.17em}}\left(n=1,2,3,\cdots \right)$ (61)

with νn the photons admitted frequency along the n-th circular orbit and since, as claimed on Section 1.4, ν (=n/t) is the number of photons (of the same ray) crossing an observer during the time t, the integer n represents the number of photons absorbed by the electron during the photon-electron impact time t and this number, for all the H atom circular orbits, is an integer starting with 1 along the electron ground-state orbit.

The massiveness of light implies a finite impact time during which the electron is circling, and supposing, for now, that, for n = 1, the photon frequency ν0 should be equal to the electron frequency along the ground-state orbit, that is νe0 = υ0/2πr0, where r0, see conf. (c) is the electron ground-state orbit, with υ0 its orbital speed, we could write

${\nu }_{0}/{\nu }_{\text{e}0}=\text{1}$ (first assumption); (62)

to verify this ratio or to find the correct value, we may start from the experimental value of the 1H ground-state ionization energy W0 (electron extraction work) corresponding to

${W}_{0}=-{U}_{r0}/2={e}^{2}/8\pi {\epsilon }_{0}{r}_{0}=½{m}_{r}{\upsilon }_{0}^{2}\cong 13.8954\text{\hspace{0.17em}}\text{eV}$ (63)

with ${U}_{r0}=-{e}^{2}/4\pi {\epsilon }_{0}{r}_{0}$ the potential of the dipole electron-proton, yielding

${r}_{0}={e}^{2}/{W}_{0}8\pi {\epsilon }_{0}\cong 5.29461×{10}^{-11}\text{\hspace{0.17em}}\text{m}$ (64)

(rough value of the Bohr radius), thus the orbital speed of the electron along ${r}_{0}$ becomes

${\upsilon }_{0}=\sqrt{{e}^{2}/4\pi {\epsilon }_{0}{r}_{0}{m}_{r}}\cong 2.18770×{10}^{6}\text{\hspace{0.17em}}\text{m}/\text{s}$ (65)

Then, if W0 is supplied by one ray of light (with energy E = hν0) it must be

$½{m}_{r}{\upsilon }_{0}^{2}=h{\upsilon }_{0}⇒{\nu }_{0}={m}_{r}{\upsilon }_{0}^{2}/2h\cong 3.28808×{10}^{15}{\text{s}}^{-1}$ (66)

with ${\nu }_{0}$ the admitted frequency along r0; hence, the ratio ν0e0 becomes

${\upsilon }_{0}/{\upsilon }_{\text{e0}}=\left({T}_{\text{e0}}/{T}_{0}\right)={\upsilon }_{0}2\pi {r}_{0}/{\upsilon }_{0}=0.499998$ (67)

meaning that during one electron orbit it should transit half of a photon, so we may infer that along r0 it should be

$2{T}_{\text{e0}}/{T}_{0}=2{\nu }_{0}/{\nu }_{\text{e0}}=1$ exact (68)

meaning that, along ${r}_{0}$ the impact time ${T}_{0}$ lasts for two electron circular orbits.

Now, see conf. (c) equating along r0 the electron centrifugal force to the Coulomb force we have

${m}_{r}{\upsilon }_{0}^{2}/{r}_{0}=\frac{{e}^{2}}{4\pi {\epsilon }_{0}{r}_{0}^{2}}⇒{m}_{r}{\upsilon }_{0}^{2}={e}^{2}/4\pi {\epsilon }_{0}{r}_{0}=-{U}_{r0}$ (69)

which, for a circular orbit, and since, see (66), ${m}_{r}{\upsilon }^{2}=2h\nu$ , gives

${\nu }_{n}={e}^{2}/4\pi {\epsilon }_{0}{r}_{n}2h$ (70)

then

${r}_{n}={e}^{2}/8\pi {\epsilon }_{0}h{\nu }_{n}={e}^{2}{n}^{2}/8\pi {\epsilon }_{0}h{\nu }_{0}={r}_{0}{n}^{2}$ (71)

while as for the orbital speed of the electron mr along any circular orbit ${r}_{n}$ the (65) gives

${\upsilon }_{n}^{2}={e}^{2}/4\pi {\epsilon }_{0}{r}_{n}{m}_{r}={e}^{2}/4\pi {\epsilon }_{0}{r}_{0}{n}^{2}{m}_{r}={\upsilon }_{0}^{2}/{n}^{2}⇒{\upsilon }_{n}={\upsilon }_{0}/n$ (72)

and finally the electron frequency along a circular orbit becomes

${\nu }_{\text{e}n}={\upsilon }_{n}/2\pi {r}_{n}={\upsilon }_{0}/n2\pi {r}_{0}{n}^{2}={\nu }_{\text{e}0}/{n}^{3}$ . (73)

Now, along r0, the (70) yields

${\nu }_{0}={e}^{2}/4\pi {\epsilon }_{0}{r}_{0}2h={e}^{2}c/2{\epsilon }_{0}hc4\pi {r}_{0}=\alpha c/4\pi {r}_{0}$ (74)

with α = e2/2ε0hc the fine structure constant and given $2{\nu }_{0}/{\nu }_{\text{e0}}=1$ (exact) we have

${\delta }_{1}\equiv 2{\nu }_{0}/{\nu }_{\text{e0}}=\left(2\alpha c/4\pi {r}_{0}\right)/\left({\upsilon }_{0}/2\pi {r}_{0}\right)=ac/{\upsilon }_{0}=1$ (75)

yielding

${\upsilon }_{0}=\alpha c={e}^{2}/2h{\epsilon }_{0}=2187691.2\text{\hspace{0.17em}}\text{m}/\text{s}$ (76)

and then the (66) becomes

${\upsilon }_{0}={m}_{r}{\upsilon }_{0}^{2}/2h={m}_{r}{\alpha }^{2}{c}^{2}/2h={R}_{\text{H}}c$ (77)

where ${R}_{\text{H}}={m}_{r}{\alpha }^{2}c/2h=1/{\lambda }_{0}$ is the Rydberg constant.

Now, from (61) and (73), because of the ratio ${\delta }_{1}\equiv 2{\nu }_{0}/{\nu }_{\text{e0}}=1$ , we also get

${\delta }_{n}\equiv 2{\nu }_{n}/{\nu }_{\text{e}n}=\left(2{\nu }_{0}/{n}^{2}\right)/\left({\nu }_{\text{e}0}/{n}^{3}\right)=n\text{\hspace{0.17em}}\text{\hspace{0.17em}}\left(\text{with}\text{\hspace{0.17em}}n=1,2,3,\cdots \right)$ (78)

which written as nTn = 2Ten shows that the impact time nTn of n photons (with frequency νn) equals the time the electron needs for two orbits along any circular orbit rn.

Now the correct value of r0, from (71), becomes

${r}_{0}=\frac{{e}^{2}}{8\pi {\epsilon }_{0}h{\nu }_{0}}=\frac{{e}^{2}}{8\pi {\epsilon }_{0}h{R}_{\text{H}}c}=\frac{\alpha }{4\pi {R}_{\text{H}}}=5.294654×{10}^{-11}\text{\hspace{0.17em}}\text{m}$ (79)

which should represent the electron ground state orbit if the electron should circle, together with its charge, around r0: indeed the ground-state effective orbit of the electron barycentre observed from mp is ${{r}^{\prime }}_{0}$ . Then, writing the (59) as ${r}_{\text{B}}={r}_{0}/\left(1+{\epsilon }_{m}\right)$ we get

${r}_{\text{B}}=\frac{{r}_{0}}{1+\frac{{m}_{\text{e}}}{{m}_{\text{P}}}}=\alpha /4\pi {R}_{\text{H}}\left(1+{\epsilon }_{m}\right)=\frac{\alpha }{4\pi {R}_{\infty }}=5.291772×{10}^{-11}\text{\hspace{0.17em}}\text{m}$ (80)

corresponding to the Bohr radius which, on our results, is the orbit of the electron charge referred to B(centre of mass of the system electron-proton)see Figure 9(a).

Now, still referring to conf. (c), the effective electron orbit (i.e. its barycenter) is ${{r}^{\prime }}_{0}$ where its effective speed is

$\begin{array}{c}{{\upsilon }^{\prime }}_{0}=\frac{{\upsilon }_{0}{{r}^{\prime }}_{0}}{{r}_{0}}=\frac{{\upsilon }_{0}\left({r}_{0}+{r}_{\text{e}}\right)}{{r}_{\text{B}}\left(1+{\epsilon }_{m}\right)}={\upsilon }_{0}\left[{r}_{\text{B}}\left(1+{\epsilon }_{m}\right)+{\epsilon }_{r}{r}_{\text{B}}\right]/{r}_{\text{B}}\left(1+{\epsilon }_{m}\right)\\ =\frac{{\upsilon }_{0}\left(1+{\epsilon }_{m}+{\epsilon }_{r}\right)}{1+{\epsilon }_{m}}=\alpha c\left(1+\frac{{\epsilon }_{r}}{1+{\epsilon }_{m}}\right)\end{array}$ (81)

and since the distance between the electron charge and the proton charge is r0 (either considering the electron circling along ${{r}^{\prime }}_{0}$ or r0), it turns out that along ${{r}^{\prime }}_{0}$ the photon admitted frequency is ${{\nu }^{\prime }}_{0}={\nu }_{0}$ , and therefore we get

${{\delta }^{\prime }}_{1}=\frac{2{\nu }_{0}}{{{\nu }^{\prime }}_{\text{e0}}}=2{\nu }_{0}/\left({{\upsilon }^{\prime }}_{0}/2\pi {{r}^{\prime }}_{0}\right)=2{\nu }_{0}/\frac{{\upsilon }_{0}{{r}^{\prime }}_{0}}{{r}_{0}}/2\pi {{r}^{\prime }}_{0}=2{\nu }_{0}2\pi {r}_{0}/{\upsilon }_{0}=1$ (82)

meaning one photon every two electron ground-state orbit, and since ${{r}^{\prime }}_{0}=\left({r}_{0}+{r}_{\text{e}}\right)$ is also a circular orbit, the effective electron orbit ${{r}^{\prime }}_{n}$ has following parameters:

${{r}^{\prime }}_{n}={{r}^{\prime }}_{0}{n}^{2};\text{\hspace{0.17em}}\text{\hspace{0.17em}}{{\upsilon }^{\prime }}_{n}={{\upsilon }^{\prime }}_{0}/n;\text{\hspace{0.17em}}\text{\hspace{0.17em}}{{\nu }^{\prime }}_{\text{e}n}={{\nu }^{\prime }}_{\text{e}0}/{n}^{3};\text{\hspace{0.17em}}\text{\hspace{0.17em}}{{\nu }^{\prime }}_{n}={\nu }_{n}$ (83)

thus for each circular orbit we get

${{\delta }^{\prime }}_{n}=\frac{2{\nu }_{n}}{{{\nu }^{\prime }}_{\text{e}n}}=\left(2{\nu }_{0}/{n}^{2}\right)/\left({{\nu }^{\prime }}_{\text{e}0}/{n}^{3}\right)=2n{\nu }_{0}/{{\nu }^{\prime }}_{\text{e}0}=n$ (84)

the same as along ${r}_{n}$ .

To apply properly the Conservation of momentum (CoM) to the impact photon-electron, the atom nucleus has to be considered fixed as origin in the common centre of gravity nucleus-electrons. On H atom, referring to Figure 9(c), an inelastic impact photon-electron, since photon and w, see Figure 8, have same direction, the (52), gives

$w=2mc/{m}_{r}=2\gamma \nu c/{m}_{r}=2\gamma \nu {c}^{2}/c{m}_{r}=2h\nu /c{m}_{r}$ (85)

where the frequency ν, see (70), depends on the effective distance r between the proton and the electron charge, while the term w, see also Figure 10, is the electron radial speed originated by the impact of one photon during the impact time T (=1/ν); for n photons of the same ray the (85) gives

Figure 10. H atom: orbital and radial electron speed, see also Figure 9(c). (a) Along r0 we have: ${\upsilon }_{0}=\alpha c;{w}_{0}={\alpha }^{2}c$ ; then, along ${{r}^{\prime }}_{0}$ we will find ${{\upsilon }^{\prime }}_{0}=c/137$ ; (b) Along the ionization orbit: ${w}_{{n}^{2}}={{\upsilon }^{\prime }}_{n}=c/{137}^{2}$ .

${w}_{n}=nw=2nh\nu /c{m}_{r}$ (86)

while the generic condition

$w=\upsilon$ (ionization condition) (87)

where $\upsilon$ is the electron speed along the ionization orbit, represents the sufficient condition for an electron to escape from its atom, (with zero final velocity of the electron, like on Absorption effect and, of course, for H atom).

Now, writing the (66) as ${\nu }_{0}={m}_{r}{\upsilon }_{0}^{2}/2h$ , the ( 85) leads to

${w}_{0}=\frac{2h{m}_{r}{\upsilon }_{0}^{2}}{2hc{m}_{r}}={\upsilon }_{0}^{2}/c={\alpha }^{2}c=15964.35\text{\hspace{0.17em}}\text{m}/\text{s}\cong c/{\text{137}}^{\text{2}}$ (88)

thus the ionization condition along r0, for one photon only, becomes

$\frac{{w}_{0}}{{\upsilon }_{0}}=\frac{{\upsilon }_{0}}{c}=\alpha \cong 1/137\ll 1$ (89)

hence the ionization, requiring $w/\upsilon =1$ , could happen for n = 137, but the number of admitted photons, along r0, is n = 1. Now, along the progressive orbit # n, the admitted photons frequency is ${\nu }_{n}={\nu }_{0}/{n}^{2}$ , and since n is the number of admitted photons along each electron circular d-orbit, we may infer that each progressive orbit is composed of n electron d-orbits, yielding n2 admitted photons along each of these orbits.

Referring now to the electron effective ground-state orbit ${{r}^{\prime }}_{0}$ , regarding the orbit ${{r}^{\prime }}_{n}\equiv {{r}^{\prime }}_{0}{n}^{2}$ , where ${{\upsilon }^{\prime }}_{n}={\upsilon }^{\prime }/n$ , the (86), for n2 photons, gives

${w}_{{n}^{2}}\left(=n{w}_{#n}\right)=\frac{{n}^{2}2h{{\nu }^{\prime }}_{n}}{c{m}_{r}}=\frac{{n}^{2}2h{{\nu }^{\prime }}_{0}}{c{m}_{r}{n}^{2}}=\frac{2h{{\nu }^{\prime }}_{0}}{c{m}_{r}}$ (90)

constant along every circular orbit, and where ${{\nu }^{\prime }}_{0}$ from (66) becomes

${{\nu }^{\prime }}_{0}={m}_{r}{{\upsilon }^{\prime }}_{0}^{2}/2h$ (91)

which represents the photon virtual frequency, intending the admitted frequency if the electron charge would be coincident with the electron barycenter along its effective orbit ${{r}^{\prime }}_{0}$ ; indeed, the photons admitted frequency is related to the effective distance r0, where the effective photon frequency is therefore ${\nu }_{0}$ . In fact, we introduce ${{\nu }^{\prime }}_{0}$ to determine the value of ${{\upsilon }^{\prime }}_{0}$ (ground-state electron effective orbital speed).

Therefore the ionization condition along ${{r}^{\prime }}_{n}$ becomes

${w}_{{n}^{2}}={{\upsilon }^{\prime }}_{n}={{\upsilon }^{\prime }}_{0}/n$ (92)

yielding

$2h{{\nu }^{\prime }}_{0}/c{m}_{r}={{\upsilon }^{\prime }}_{0}/n⇒n={{\upsilon }^{\prime }}_{0}c{m}_{r}/2h{{\nu }^{\prime }}_{0}$ (93)

then

$n={{\upsilon }^{\prime }}_{0}c{m}_{r}2h/2h{m}_{r}{{\upsilon }^{\prime }}_{0}^{2}⇒n=\frac{c}{{{\upsilon }^{\prime }}_{0}}\cong \frac{c}{{\upsilon }_{0}}=\frac{c}{\alpha c}\cong 137$ (94)

but n has to be in integer, so we can infer $n=c/{{\upsilon }^{\prime }}_{0}=137$ and therefore we get

${{\upsilon }^{\prime }}_{0}=c/137$ (95)

representing the electron speed along its effective ground-state orbit, while

${{\upsilon }^{\prime }}_{137}={{\upsilon }^{\prime }}_{0}/137=c/{137}^{2}$ (96)

represents the electron speed along its ionization orbit, see also Table 2.

Then, since ${{\upsilon }^{\prime }}_{0}=\alpha c\left(1+\frac{{\epsilon }_{r}}{1+{\epsilon }_{m}}\right)$ we obtain

$\frac{c}{137}=\frac{\alpha c\left(1+{\epsilon }_{m}+{\epsilon }_{r}\right)}{1+{\epsilon }_{m}}$ (97)

then

$1+{\epsilon }_{m}+{\epsilon }_{r}=\frac{\left(1+{\epsilon }_{m}\right)}{137\alpha }⇒{\epsilon }_{r}=\left(1+{\epsilon }_{m}\right)\left(\frac{1}{137\alpha }-1\right)=0.0002629141$ (98)

and since, for definition, ${r}_{\text{e}}={\epsilon }_{r}{r}_{\text{B}}$ , we get

${r}_{\text{e}}={\epsilon }_{r}{r}_{\text{B}}=\frac{{\epsilon }_{r}\alpha }{4\pi {R}_{\infty }}=\left(1+{\epsilon }_{m}\right)\left(\frac{1}{137\alpha }-1\right)\alpha /4\pi {R}_{\infty }=\left(\frac{1}{137\alpha }-1\right)\alpha /4\pi {R}_{\text{H}}$ (99)

and since $4\pi {R}_{\text{H}}=\alpha /{r}_{0}$ we also get

${r}_{\text{e}}=\left(\frac{1}{137\alpha }-1\right){r}_{0}=1.391281×{10}^{-14}\text{m}$ (electron radius) (100)

Table 2. Parameters of H atom circular orbits up to the ionization, our results.

2.5. Absorption/Emission Effect; Claimed Fall of Circling Electrons

Referring to Figure 11 representing the Absorption of photons into a circling electron, let us assume the nucleus mass mN >> me so to consider the nucleus fixed in the atom centre of gravity B.

Now, the expression of the total energy of the system photon-electron is given by

$T=E+{U}_{r}+{K}_{\text{e}}+{K}_{r}$ (101)

where E (=mc2) is the energy of the incident light, Ur (=−e2/4πε0r) is the potential due to electrostatic attraction acting on the electron, Ke (=½meυ2) is the electron orbital kinetic energy, and Kr (=½mew2) its radial kinetic energy related to its radial speed w due to the impact photon-electron.

Regarding the Absorption/Emission effect (elements on gaseous state), see Figure 11, along circular orbits it is Kr = 0 and moreover, at the end of absorption, along the orbit r2, (where the photons have been absorbed), it is E2 = 0; hence between two circular orbits r1 and r2, the (101) gives

${E}_{1}+{U}_{r1}+{K}_{\text{e}1}={U}_{r2}+{K}_{\text{e}2}.$ (102)

Now, from (69) Ur = −meυ2 and since Ke = ½meυ2, we get $\left({U}_{r}+{K}_{e}\right)=-½{m}_{\text{e}}{\upsilon }^{2}$ thus from (102) we get ${E}_{1}-½{m}_{\text{e}}{\upsilon }_{1}^{2}=-½{m}_{\text{e}}{\upsilon }_{2}^{2}$ ; so, as E1 = hn, and since meυ2 = e2/4πε0r we find

$h\nu =½{m}_{\text{e}}{\upsilon }_{1}^{2}-½{m}_{\text{e}}{\upsilon }_{2}^{2}=\frac{{e}^{2}}{8\pi {\epsilon }_{0}}\left(\frac{1}{{r}_{1}}-\frac{1}{{r}_{2}}\right)$ (103)

Then, according to (71) we have r1 = r0n2 and r2 = r0k2 (with k > n as r2 > r1), thus

Figure 11. Absorption/Emission effect: (a) Incident photons are absorbed by the electron which moves toward wider orbits; (b) Emission: the electron moves toward inner orbits emitting photons.

$\nu =\left(\frac{{e}^{2}}{8\pi {\epsilon }_{0}h{r}_{0}}\right)\left(\frac{1}{{n}^{2}}-\frac{1}{{k}^{2}}\right)$ (104)

and plugging the (74) written as ν0 = e2/8πε0hr0, we find

$\nu ={\nu }_{0}\left(\frac{1}{{n}^{2}}-\frac{1}{{k}^{2}}\right)$ (105)

which is the photons frequency between two circular orbits, where n represents the progressive specific number of each circular orbit and where k turns out to have, for each of them, the values k = n + 1, n + 2, ∙∙∙, ni which are, one by one, the number of the remaining external circular orbits, and where ni is the ionization orbit; on H atom, ni = 137.

Claimed fall of a circling electron into its nucleus: an electrical current emits an electro-magnetic radiation and therefore it is claimed that the circulating electrical charge of an electron should also emit an e.m. radiation yielding the electron, in a short time, to fall into the nucleus; but on our results, a free electron, moving, for instance, along a copper wire under an electrical potential difference, when entering into an atom influence, (at that moment the electron charge will return to face the atom nucleus), will release the necessary photons to reach the atom energy level corresponding to the energy previously received (during the absorption effect). Indeed, along circular orbits, it is w = 0, therefore the absorption/emission of photons cannot happen along circular orbit, that is why the circling electrons are absorbing/emitting photons only between circular orbits, and therefore, the e.m. radiation is due to the emitted photons during their re-entry toward inner orbits; at this regard, the photons emission is necessary for the electrons not to fall into their nucleus.

2.6. Photoelectric Effect: Number of Involved Photons

Between the electron ground-state orbit r0 and its extraction orbit r ® ¥ (intending on microscopic scale), the (101), valid for every interaction light-matter, gives

$E+{U}_{r0}+{K}_{\text{e}0}+{K}_{r0}={E}^{\prime }+{U}_{r\to \infty }+{K}_{\text{e}\infty }+{K}_{\text{ae}}$ (106)

where E' is the energy of re-emitted light, ${K}_{\text{ae}}=½{m}_{\text{e}}{w}_{\text{ae}}^{2}$ the electron kinetic energy after its extraction (intending on macroscopic scale), wae its related radial speed, while the other terms have been defined referring to (101).

On ground-state, as also shown between Equations (102) and (103), it is

${U}_{r0}+{K}_{\text{e}0}=-{m}_{\text{e}}{\upsilon }_{0}^{2}+½{m}_{\text{e}}{\upsilon }_{0}^{2}=-½{m}_{\text{e}}{\upsilon }_{0}^{2}=-{W}_{\text{f}}$ (107)

with υ0 the electron speed along r0 and Wf the work function (electron extraction work); now, at the start of impact it is w = 0 giving ${K}_{r0}\left(=½{m}_{\text{e}}{w}^{2}\right)=0$ while for r ® ¥, the electron orbital speed υ¥ ® 0,so

$\left({U}_{r\to \infty }+{K}_{\text{e}0}\right)=-½{m}_{\text{e}}{\upsilon }_{\infty }^{2}\to 0$ (108)

hence the (106) gives

$E-{W}_{\text{f}}={E}^{\prime }+{K}_{\text{ae}}⇒E={E}^{\prime }+{W}_{\text{f}}+{K}_{\text{ae}}$ (109)

where ${W}_{\text{f}}+{K}_{\text{ae}}$ is the total kinetic energy transferred from light to electron, that is the sum of the sufficient energy to remove the electron plus the one to give it the energy after extraction.

On Photoelectric Effect (PhE), the light scatters off an electron (Kae ≥ 0), but it is not re-emitted, hence E' = 0, so the (109), with nf (=Wf/h) the specific threshold frequency, becomes

$E={W}_{\text{f}}+{K}_{\text{ae}}⇒h\nu =h{\nu }_{\text{f}}+½{m}_{\text{e}}{w}_{\text{ae}}^{2}$ (110)

showing that for ν = νf there is ionization with wae = 0.

At frequency νf the electron radial speed wf due to the impact of one photon, see Equation (85), is ${w}_{\text{f}}=\text{2}h{\nu }_{\text{f}}/{m}_{\text{e}}c=\text{2}{W}_{\text{f}}/{m}_{\text{e}}c$ , and writing the (66) as

${\upsilon }_{0}={\left(2h{\nu }_{\text{f}}/{m}_{\text{e}}\right)}^{1/2}={\left(2{W}_{\text{f}}/{m}_{\text{e}}\right)}^{1/2}$ (111)

we get

$\frac{{w}_{\text{f}}}{{\upsilon }_{0}}=\frac{\left(\frac{2{W}_{\text{f}}}{{m}_{\text{e}}c}\right)}{{\left(\frac{2{W}_{\text{f}}}{{m}_{\text{e}}}\right)}^{\frac{1}{2}}}={\left(\frac{2{W}_{\text{f}}}{{m}_{\text{e}}}\right)}^{½}/c=\frac{{\upsilon }_{0}}{c}⇒{w}_{\text{f}}=\frac{{\upsilon }_{0}^{2}}{c}$ (112)

which is equal to (88), and since the values of Wf are in the range @ 2 - 6 eV, the Equation (112) gives wf0 @ 0.0028 - 0.0048 meaning that the ionization (which for elements on solid state where electrons are circling along fixed orbits requires w = υ0), at frequency νf needs nf photons: indeed, the electron radial speed due to nf photons with frequency νf, see (86), is

${w}_{n\text{f}}={n}_{\text{f}}{w}_{\text{f}}={n}_{\text{f}}\text{2}{W}_{\text{f}}/{m}_{\text{e}}c$ (113)

so the ionization condition becomes ${w}_{n\text{f}}={\upsilon }_{0}$ leading to ${n}_{\text{f}}2{W}_{\text{f}}/{m}_{\text{e}}c={\left(2{W}_{\text{f}}/{m}_{\text{e}}\right)}^{½}$ giving

${n}_{\text{f}}=c/\sqrt{2{W}_{\text{f}}/{m}_{\text{e}}}=c\sqrt{{m}_{\text{e}}/2{W}_{\text{f}}}={\upsilon }_{0}/{w}_{\text{f}}=c/{\upsilon }_{0}$ (114)

that is, on PhE, the number of photons at frequency νf necessary for ionization (wae = 0). Now, if nf photons, at frequency νf, are sufficient for ionization, then the frequency

${n}_{\text{f}}{\nu }_{\text{f}}\equiv {\nu }_{1}$ (115)

is sufficient for ionization (wae = 0) with one photon only, so ν1 is the threshold between PhE and Compton effect which requires one photon only, as shown on next chapter.

To find the number n1 related to the frequency ν1 let us equate the (66) written as ${\upsilon }_{0}=\sqrt{2h{\nu }_{1}/{m}_{\text{e}}}$ , to the electron radial speed due to n1 photons, ${w}_{n1}=2nh{\nu }_{1}/c{m}_{\text{e}}$ yielding $\left(2h{\nu }_{1}/{m}_{\text{e}}\right)={\left(2{n}_{1}h{\nu }_{1}/c{m}_{\text{e}}\right)}^{2}$ and then

${n}_{1}^{2}=\frac{{m}_{\text{e}}{c}^{2}}{2h{\nu }_{1}}=\frac{{m}_{\text{e}}{c}^{2}}{2h{n}_{\text{f}}{\nu }_{\text{f}}}=\frac{{m}_{\text{e}}{c}^{2}}{2{n}_{\text{f}}{W}_{\text{f}}}⇒{n}_{1}=c\sqrt{{m}_{\text{e}}/2{n}_{\text{f}}{W}_{\text{f}}}$ (116)

and plugging ${W}_{\text{f}}={c}^{2}{m}_{\text{e}}/2{n}_{\text{f}}^{2}$ as given by (114), we find

${n}_{1}=\sqrt{{n}_{\text{f}}}$. (117)

For instance as for caesium (Cs), having Wf 1.95 eV, since ${n}_{\text{f}}=c{\left({m}_{\text{e}}/2{W}_{\text{f}}\right)}^{½}\cong 361.9$ we may infer nf = 361 leading to n1 = 19, while as for Be or Co, having Wf @ 5 eV we may infer nf = 225 leading to n1 = 15.

2.7. Compton Effect and Its Equation via Doppler Effect

Here, see Figure 12, the incident photon (length λ, frequency ν), while ejecting a circling electron is also reflected (λ', ν') so the recoiling electron, emitting a photon λ' toward the Observer A, represents a source in motion from A along the direction w, implying an undoubted Doppler effect.

Now, on the basis that the incident photon starts to be reflected at the same time when it starts to hit the electron, and since ${T}^{\prime }=1/{\nu }^{\prime }$ is the emission time of the reflected photon, it turns out that ${T}^{\prime }$ is also the whole interaction time (and this means that there is not a complete absorption of the incident photon followed by an emission). Now, with ${T}^{\prime }$ the whole impact time photon-electron, the momentum transferred from the incident light to the electron, as per (53), is

${p}^{\prime }={m}^{\prime }c=\gamma {\nu }^{\prime }c=\gamma c/{T}^{\prime }$ (118)

and the same value is then transferred from the reflected photon to the electron, so the Conservation of Momentum (CoM) along the direction normal to w, becomes

$\gamma c/{T}^{\prime }\mathrm{sin}\theta =\gamma c/T\mathrm{sin}{\theta }^{\prime }$ (119)

giving $\theta ={\theta }^{\prime }$ . Then, the length of the reflected photon, for the Observer A, see (17), is

${\lambda }^{\prime }=\lambda +\Delta \lambda$ (120)

where Δλ = wAT', where wA = wcosθ is the component of the electron speed along the direction of the Observer A, and ${T}^{\prime }=1/{\nu }^{\prime }$ is, for A, the photon transit time, so we get

${\lambda }^{\prime }-\lambda \equiv \Delta \lambda =w{T}^{\prime }\mathrm{cos}\theta$ (121)

Now the CoM along w, being $\theta ={\theta }^{\prime }$ , gives

Figure 12. Compton effect (CE). φ: angle between the direction of the incident photon and the scattered one (λ'); θ: angle between the direction of the incident photon and the recoiled electron.

$\frac{\gamma c\mathrm{cos}\theta }{{T}^{\prime }}+\frac{\gamma c\mathrm{cos}\theta }{{T}^{\prime }}={m}_{\text{e}}w⇒w{T}^{\prime }=\left(2\gamma c\mathrm{cos}\theta \right)/{m}_{\text{e}}$ (122)

so the (121) becomes

${\lambda }^{\prime }-\lambda \left(\equiv \Delta \lambda \right)=\frac{2\gamma c{\mathrm{cos}}^{2}\theta }{{m}_{\text{e}}}=\frac{2h{\mathrm{cos}}^{2}\theta }{c{m}_{\text{e}}}$ (123)

Now, $2\theta +\phi =\pi$ , $⇒\theta =\left(\pi -\phi \right)/2$ , hence $\mathrm{cos}\theta =\mathrm{sin}\phi /2$ and therefore

$\Delta \lambda =2h{\mathrm{sin}}^{2}\left(\frac{\phi }{2}\right)/c{m}_{\text{e}}$ (124)

and since $2{\mathrm{sin}}^{2}\left(\frac{\phi }{2}\right)=\left(1-\mathrm{cos}\phi \right)$ ,we get the Compton equation:

$\Delta \lambda ={\lambda }^{\prime }-\lambda =h\left(1-\mathrm{cos}\phi \right)/c{m}_{\text{e}}$ (125)

which cannot be obtained via the Doppler effect relativistic equations regarding the light.

We point out that the (122) written as $w=\left(2\gamma {\nu }^{\prime }c\mathrm{cos}\theta \right)/{m}_{\text{e}}$ , for cosθ = 1 equals the (85), implying the impact of one photon only.

Now, the (123), for cosθ = 1 gives ${\lambda }^{\prime }=\frac{c}{\nu }+\frac{2\gamma c}{{m}_{\text{e}}}$ we can write as:

${T}^{\prime }=\frac{1}{\nu }+\frac{2\gamma }{{m}_{\text{e}}}=\left({m}_{\text{e}}+2\gamma \nu \right)/\nu {m}_{\text{e}}$ (126)

which plugged into (122) gives

$w=\left(\frac{2\gamma c}{{m}_{\text{e}}}\right)/\left({m}_{\text{e}}+2\gamma \nu \right)/\nu {m}_{\text{e}}=\frac{2\gamma \nu c}{2\gamma \nu +{m}_{\text{e}}}=\frac{c}{1+{m}_{\text{e}}/2\gamma \nu }$ (127)

yielding w → c for ν → ∞.

3. Conclusions

This paper is mainly based on three conditions: c = u (with u the total escape speed); a certain structure of the light (massive photons having variable length); the electron charge like a point-particle facing the atom nucleus during the electron orbit.

On these bases, we gave a classical reason to the apparent constancy of c, then we showed that the time dilation turns out to be an effect of the variation of the total gravitational potential U (inducing a variation of c) and we also showed that the high gravitational red shifts are also due to the same reason; we also showed that the quantum numbers are nothing else than the numbers of photons admitted on free atoms along an integer number of electron orbits; then we gave a reason why the circling electrons cannot fall into their nucleus, and we also showed that the ionization of free atoms happens when the electron radial speed (due to the impact photons-electron) equals the electron orbital speed.

Cite this paper
Bacchieri, A. (2018) Three Conditions Leading to a Unified (Quasi-Newtonian) Physics. Journal of Modern Physics, 9, 2045-2072. doi: 10.4236/jmp.2018.911129.
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