1. Introduction and preliminaries

In [1] , Khan introduced and proved fixed point results by the altering distance in metric space. Aliouche [2] proved common fixed point results in symmetric space for weakly compatible mappings under contractive condition of integral type. In [3] , Babu generalized and proved fixed point results using control function. Later Bouhadjera and Godet [4] generalized concept of pair sub compatible maps and proved fixed point results. Also Chaudhari [5] [6] , Chugh & Kumar [7] , Naidu [8] , Sastry et al. [9] generalized and proved some fixed point results. Recently in [10] [11] , Hosseni used contractive rule of integral type by altering distance and generalized common fixed point results. Many authors proved fixed point results with different techniques in different spaces (see [12] - [17] ). In [18] [19] [20] [21] , Wadkar et al. proved fixed point theorems using the concept of soft metric space. In the present paper, we prove two theorems on fixed point under contraction rule of integral type in metric space by altering distance function, first for self map and second for a pair of sub compatible maps. Our results are motivated by V. R. Hosseni, Neda Hosseni.

Definition 1.1: A function $\psi :R^{+}\to R^{+}=\left[0,1\right)$ is an altering distance functions if $\psi$ is continuous with monotone increasing in all variables and $\psi \left(x_1,x_2,x_3,\cdots ,x_n\right)=0$ if $x_1=x_2=x_3=\cdots =x_n=0.$

The collection of all altering distance is denoted by ${\Psi }_n$ .

Now let us define a function $m\left(y\right)$ by $m\left(y\right)=\psi \left(y,y,y,y,\cdots ,y\right)$ for $y\in \left[0,\infty \right)$ , clearly $m\left(y\right)=0$ if and only if $y=0$ .

Examples of $\psi$ are $\psi \left(f_1,f_2,f_3,\cdots ,f_n\right)=\mu \max \left\{f_1,f_2,f_3,\cdots ,f_n\right\},$ for $\mu >0$ , (1)

$\psi \left(f_1,f_2,f_3,\cdots ,f_n\right)=f_n^{a_1}+f_n^{a_2}+f_n^{a_3}+\cdots +f_n^{a_n},a_1,a_2,\cdots ,a_n\ge 1.$ (2)

Definition 1.2: The maps $p,q:E\to E$ of metric space $\left(E,\sigma \right)$ are called as sub compatible if and only if the sequence $\left\{e_n\right\}$ in E such that $\underset{n\to \infty }{\lim }{p}_n=\underset{n\to \infty }{\lim }{q}_n=t,t\in E$ and which satisfies $\underset{n\to \infty }{\lim }\sigma \left(pq{e}_n,qp{e}_n\right)=0.$

Example 1.3: Let $E=\left[0,\infty \right)$ we define p & q with metric $\sigma$ as follows

$p\left(e\right)=e^2$ & $q\left(e\right)=\{\begin{array}{l}e+6\text{if}e\in \left[4,9\right]\cup \left(27,\infty \right)\hfill \\ e^2,\text{if}e\in \left[9,27\right]\hfill \end{array}$ (3)

Let us define the sequence $\left\{e_n\right\}$ in E as $e_n=3+\frac{1}{n}$ , for $n=0,1,2,\cdots$ then

$\underset{n\to \infty }{\lim }p{e}_n=\underset{n\to \infty }{\lim }{e}_n^2=9=\underset{n\to \infty }{\lim }q{e}_n=\underset{n\to \infty }{\lim }\left(e_n+6\right),$ (4)

and $\underset{n\to \infty }{\lim }pq\left(e_n\right)=\underset{n\to \infty }{\lim }p\left(e_n+6\right)=\underset{n\to \infty }{\lim }{\left(e_n+6\right)}^2=81\text{when}n\to \infty ,$ (5)

$\underset{n\to \infty }{\lim }qp{e}_n=\underset{n\to \infty }{\lim }q{e}_n^2={\left(e_n^2\right)}^2=\underset{n\to \infty }{\lim }{\left(e_n\right)}^4=81\text{when}n\to \infty .$ (6)

Thus, we have $\underset{n\to \infty }{\lim }\sigma \left(pq{e}_n,qp{e}_n\right)=0$ . (7)

Hence maps p and q are sub-compatible.

On the other hand, we have $pe=qe$ if and only if $e=3$ , $pq\left(3\right)=p\left(9\right)=81$ and $qp\left(3\right)=q\left(9\right)=9+6=15.$

Then $p\left(3\right)=9=q\left(3\right)$ but $pq\left(3\right)=81\ne 15=qp\left(3\right)$ , hence p and q are not OWC (Oscillatory weakly commuting).

2. Main Result

Theorem 2.1: Let us consider the mappings $U,V:E\to E$ of complete metric space $\left(E,\sigma \right)$ be such that for all $c,d\in E$

$\begin{array}{c}{\displaystyle {\int }_0^{{\varphi }_1\left(\sigma \left(Uc,Vd\right)\right)}\eta \left(y\right)\text{d}y}\le {\displaystyle {\int }_0^{{\psi }_1\left(\sigma \left(c,d\right),\sigma \left(Uc,,c\right),\sigma \left(Vd,d\right),\frac{1}{2}\left\{\sigma \left(Vd,c\right)+\sigma \left(Uc,d\right)\right\},\frac{1}{2}\left\{\sigma \left(c,d\right)+\sigma \left(Uc,c\right)\right\}\right)}\eta \left(y\right)\text{d}y}\\ -{\displaystyle {\int }_0^{{\psi }_2\left(\sigma \left(c,d\right),\sigma \left(Uc,,c\right),\sigma \left(Vd,d\right),\frac{1}{2}\left\{\sigma \left(Vd,c\right)+\sigma \left(Uc,d\right)\right\},\frac{1}{2}\left\{\sigma \left(c,d\right)+\sigma \left(Uc,c\right)\right\}\right)}\eta \left(y\right)\text{d}y},\end{array}$ (8)

where ${\psi }_1,{\psi }_2\in {\Psi }_5$ with ${\varphi }_1=\psi \left(e,e,e,e,e\right)$ , $e\in \left[0,\infty \right)$ and Lebesgue-integr- able mapping $\eta :R^{+}\to R^{+}$ , which is positive, sum able, and for each $\in >0,{\displaystyle {\int }_0^{\in }\eta \left(y\right)\text{d}y>0}$ , then there exist a unique common fixed point in E for U and V.

Proof: Consider arbitrary point $e_0$ of E, for $n=1,2,3,\cdots$ we have

$e_{2n+1}=U{e}_{2n}$

and $e_{2n+2}=V{e}_{2n+1}$ .

Let $r_n=\sigma \left(e_n,e_{n+1}\right)$ (9)

Substituting $c=e_{2n}$ and $d=e_{2n+1}$ in Equation (8), then for all $n=1,2,3,\cdots$ we have

$\begin{array}{l}{\displaystyle {\int }_0^{{\varphi }_1\left(\sigma \left(U{e}_{2n},V{e}_{2n+1}\right)\right)}\eta \left(y\right)\text{d}y}\le {\displaystyle {\int }_0^{{\varphi }_1\left(\sigma \left(e_{2n+1},e_{2n+2}\right)\right)}\eta \left(y\right)\text{d}y}\\ \le {\displaystyle {\int }_0^{{\psi }_1\left(\sigma \left(e_{2n},e_{2n+1}\right),\sigma \left(U{e}_{2n},e_{2n}\right),\sigma \left(V{e}_{2n+1},e_{2n+1}\right),\frac{1}{2}\left\{\begin{array}{l}\sigma \left(V{e}_{2n+1},e_{2n}\right)\\ +\sigma \left(U{e}_{2n},e_{2n+1}\right)\end{array}\right\},\frac{1}{2}\left\{\begin{array}{l}\sigma \left(e_{2n},e_{2n+1}\right)+\\ \sigma \left(U{e}_{2n},e_{2n}\right)\end{array}\right\}\right)}\eta \left(y\right)\text{d}y}\\ -{\displaystyle {\int }_0^{{\psi }_2\left(\sigma \left(e_{2n},e_{2n+1}\right),\sigma \left(U{e}_{2n},e_{2n}\right),\sigma \left(V{e}_{2n+1},e_{2n+1}\right),\frac{1}{2}\left\{\begin{array}{l}\sigma \left(V{e}_{2n+1},e_{2n}\right)\\ +\sigma \left(U{e}_{2n},e_{2n+1}\right)\end{array}\right\},\frac{1}{2}\left\{\begin{array}{l}\sigma \left(e_{2n},e_{2n+1}\right)\\ +\sigma \left(U{e}_{2n},e_{2n}\right)\end{array}\right\}\right)}\eta \left(y\right)\text{d}y}\\ \le {\displaystyle {\int }_0^{{\psi }_1\left(\sigma \left(e_{2n},e_{2n+1}\right),\sigma \left(e_{2n+1},e_{2n}\right),\sigma \left(e_{2n+2},e_{2n+1}\right),\frac{1}{2}\left\{\begin{array}{l}\sigma \left(e_{2n+2},e_{2n}\right)\\ +\sigma \left(e_{2n+1},e_{2n+1}\right)\end{array}\right\},\frac{1}{2}\left\{\begin{array}{l}\sigma \left(e_{2n},e_{2n+1}\right)\\ +\sigma \left(e_{2n+1},e_{2n}\right)\end{array}\right\}\right)}\eta \left(y\right)\text{d}y}\\ -{\displaystyle {\int }_0^{{\psi }_2\left(\sigma \left(e_{2n},e_{2n+1}\right),\sigma \left(e_{2n+1},e_{2n}\right),\sigma \left(e_{2n+2},e_{2n+1}\right),\frac{1}{2}\left\{\begin{array}{l}\sigma \left(e_{2n+2},e_{2n}\right)\\ +\sigma \left(e_{2n+1},e_{2n+1}\right)\end{array}\right\},\frac{1}{2}\left\{\begin{array}{l}\sigma \left(e_{2n},e_{2n+1}\right)\\ +\sigma \left(e_{2n+1},e_{2n}\right)\end{array}\right\}\right)}\eta \left(y\right)\text{d}y}\end{array}$

Using Equation (9) for all $n=1,2,3,\cdots$ we get

$\begin{array}{c}{\displaystyle {\int }_0^{{\varphi }_1\left(r_{2n+1}\right)}\eta \left(y\right)\text{d}y}\le {\displaystyle {\int }_0^{{\psi }_1\left(r_{2n},r_{2n},r_{2n+1}\frac{1}{2}\left\{r_{2n+1}+r_{2n}+0\right\},\frac{1}{2}\left\{r_{2n}+r_{2n}\right\}\right)}\eta \left(y\right)\text{d}y}\\ -{\displaystyle {\int }_0^{{\psi }_2\left(r_{2n},r_{2n},r_{2n+1}\frac{1}{2}\left\{r_{2n+1}+r_{2n}+0\right\},\frac{1}{2}\left\{r_{2n}+r_{2n}\right\}\right)}\eta \left(y\right)\text{d}y}\end{array}$ (10)

As $r_{2n+1}>r_{2n}$ implies that $r_{2n+1}+r_{2n}\le 2r_{2n+1}$ , so we have

${\displaystyle {\int }_0^{{\varphi }_1\left(r_{2n+1}\right)}\eta \left(y\right)\text{d}y}\le {\displaystyle {\int }_0^{{\psi }_1\left(r_{2n},r_{2n},r_{2n+1}{r}_{2n+1},r_{2n}\right)}\eta \left(y\right)\text{d}y}={\displaystyle {\int }_0^{{\varphi }_1\left(r_{2n+1}\right)}\eta \left(y\right)\text{d}y}$ (11)

Now by monotone increase of ${\psi }_1$ in all variables and using the property that ${\psi }_2\left(r_{2n},r_{2n},r_{2n+1},r_{2n+1},r_{2n}\right)\ne 0$ whenever $r_{2n+1}\ne 0$ , we get a contradiction i.e. $r_{2n+1}$ not greater than $r_{2n}$ . Hence we have $r_{2n+1}\le r_{2n}$ , for

$n=0,1,2,3,\cdots$ (12)

Substituting $c=e_{2n-1},d=e_{2n}$ in Equation (8) we have

${\displaystyle {\int }_0^{{\varphi }_1\left(r_{2n}\right)}\eta \left(y\right)\text{d}y}\le {\displaystyle {\int }_0^{{\psi }_1\left(r_{2n-1},r_{2n-1},r_{2n},r_{2n},r_{2n-1}\right)}\eta \left(y\right)\text{d}y}-{\displaystyle {\int }_0^{{\psi }_2\left(r_{2n-1},r_{2n-1},r_{2n},r_{2n},r_{2n-1}\right)}\eta \left(y\right)\text{d}y}$ (13)

By using (12) we consider

$r_{2n+2}\le r_{2n+1}$ (14)

From (10) and (12) we obtain

$r_{n+1}\le r_n$ (15)

From (8) & (11) for all $n=1,2,3,\cdots$ , we have

${\displaystyle {\int }_0^{{\varphi }_1\left(r_{n+1}\right)}\eta \left(y\right)\text{d}y}\le {\displaystyle {\int }_0^{{\psi }_1\left(r_n\right)}\eta \left(y\right)\text{d}y}-{\displaystyle {\int }_0^{{\psi }_2\left(r_n\right)}\eta \left(y\right)\text{d}y}$

then

${\displaystyle {\int }_0^{{\varphi }_2\left(r_{n+1}\right)}\eta \left(y\right)\text{d}y}\le {\displaystyle {\int }_0^{{\varphi }_1\left(r_n\right)}\eta \left(y\right)\text{d}y}-{\displaystyle {\int }_0^{{\varphi }_1\left(r_{n+1}\right)}\eta \left(y\right)\text{d}y}$

Taking summation in above equation we obtain

${\displaystyle \underset{0}{\overset{\infty }{\sum }}{\displaystyle {\int }_0^{{\varphi }_2\left(r_{n+1}\right)}\eta \left(y\right)\text{d}y}}\le {\displaystyle {\int }_0^{{\varphi }_1\left(r_0\right)}\eta \left(y\right)\text{d}y}<\infty$ ,

which implies ${\varphi }_2\left(r\right)\to 0$ as $n\to \infty$ . (16)

Now from (13) sequence $\left\{r_n\right\}$ is convergent and as $n\to \infty$ , $r_n\to r.$ We know that $\varphi$ is continuous and from Equation (14) we obtain ${\varphi }_2\left(r\right)=0$ which implies that $r=0$ , i.e. as

$n\to \infty ,$ $r=\sigma \left(e_{n+1},e_n\right)\to 0.$ (17)

We now show that the sequence $\left\{e_n\right\}$ is a Cauchy sequence in E. Keeping in mind Equation (15) it is require to show that ${\left\{e_{2s}\right\}}_{s=1}^{\infty }\subset \left\{e_n\right\}$ is a Cauchy sequence. If ${\left\{e_{2s}\right\}}_{s=1}^{\infty }$ is not a Cauchy sequence of natural number $\left\{2m\left(k\right)\right\},\left\{2n\left(k\right)\right\}$ such that $n\left(k\right)>m\left(k\right)$ , $\sigma \left(e_{2m\left(k\right)},e_{2n\left(k\right)}\right)\ge \in$

$\sigma \left(e_{2m\left(k\right)},e_{2n\left(k\right)-1}\right)<\in$ (18)

Hence using (16)

$\begin{array}{l}\in <\sigma \left(e_{2m\left(k\right)},e_{2n\left(k\right)}\right)\\ \le \sigma \left(e_{2m\left(k\right)},e_{2n\left(k\right)-1}\right)+\sigma \left(e_{2n\left(k\right)},e_{2n\left(k\right)-1}\right)\\ <\in +\sigma \left(e_{2n\left(k\right)},e_{2n\left(k\right)-1}\right).\end{array}$

Taking $k\to \infty$ in the inequality above & by result of Equation (15), we arrive at

$\underset{n\to \infty }{\lim }\sigma \left(e_{2m\left(k\right)},e_{2n\left(k\right)}\right)=\in$ . (19)

For all $k=1,2,3,\cdots$

$\sigma \left(e_{2n\left(k\right)+1},e_{2m\left(k\right)}\right)\le \sigma \left(e_{2n\left(k\right)+1},e_{2n\left(k\right)}\right)+\sigma \left(e_{2n\left(k\right)},e_{2m\left(k\right)}\right)$ (20)

Also for $k=1,2,3,\cdots$

$\sigma \left(e_{2n\left(k\right)},e_{2m\left(k\right)}\right)\le \sigma \left(e_{2n\left(k\right)},e_{2n\left(k\right)+1}\right)+\sigma \left(e_{2n\left(k\right)+1},e_{2m(k)}\right)$ . (21)

Making $k\to \infty$ in (18) & (19) respectively by using (15) & (17) we have

$\underset{k\to \infty }{\lim }\sigma \left(e_{2n\left(k\right)+1},e_{2m\left(k\right)}\right)\le \in$

and $\in \le \underset{k\to \infty }{\lim }\sigma \left(e_{2n\left(k\right)+1},e_{2m\left(k\right)}\right)$

Therefore, $\underset{k\to \infty }{\lim }\sigma \left(e_{2n\left(k\right)+1},e_{2m\left(k\right)}\right)=\in$ , for $k=1,2,3,\cdots$ (22)

$\sigma \left(e_{2n\left(k\right)},e_{2m\left(k\right)-1}\right)\le \sigma \left(e_{2n\left(k\right)},e_{2m\left(k\right)}\right)+\sigma \left(e_{2m\left(k\right)},e_{2m\left(k\right)-1}\right),$

$\sigma \left(e_{2n\left(k\right)},e_{2m\left(k\right)}\right)\le \sigma \left(e_{2n\left(k\right)},e_{2m\left(k\right)-1}\right)+\sigma \left(e_{2m\left(k\right)-1},e_{2m\left(k\right)}\right).$

Taking $k\to \infty$ in the above two inequalities and using (15) & (17) we obtain

$\underset{n\to \infty }{\lim }\sigma \left(e_{2n\left(k\right)},e_{2m\left(k\right)-1}\right)=\in$ . (23)

Putting $c=e_{2n\left(k\right)},d=e_{2m\left(k\right)-1}$ in (8), for all $k=1,2,3,\cdots$ , we obtain

$\begin{array}{l}{\displaystyle {\int }_0^{{\varphi }_1\sigma \left(e_{2n\left(k\right)+1},e_{2m\left(k\right)}\right)}\eta \left(y\right)\text{d}y}={\displaystyle {\int }_0^{{\varphi }_1\sigma \left(U{e}_{2n\left(k\right)},V{e}_{2m\left(k\right)-1}\right)}\eta \left(y\right)\text{d}y}\\ \le {\displaystyle {\int }_0^{{\psi }_1\left(\sigma \left(e_{2n},e_{2m\left(k\right)-1}\right),\sigma \left(e_{2n\left(k\right)+1},e_{2n}\right),\sigma \left(e_{2m\left(k\right)},e_{2m\left(k\right)-1}\right),\frac{1}{2}\left\{\begin{array}{l}\sigma \left(e_{2m\left(k\right)},e_{2n\left(k\right)}\right)\\ +\sigma \left(e_{2n\left(k\right)+1},e_{2m\left(k\right)-1}\right)\end{array}\right\},\frac{1}{2}\left\{\begin{array}{l}\sigma \left(e_{2n\left(k\right)},e_{2m\left(k\right)-1}\right)\\ +\sigma \left(e_{2n\left(k\right)+1},e_{2n}\left(k\right)\right)\end{array}\right\}\right)}\mathrm{\eta (y)dy}}\\ -{\displaystyle {\int }_0^{{\psi }_2\left(\sigma \left(e_{2n},e_{2m\left(k\right)-1}\right),\sigma \left(e_{2n\left(k\right)+1},e_{2n}\right),\sigma \left(e_{2m\left(k\right)},e_{2m\left(k\right)-1}\right),\frac{1}{2}\left\{\begin{array}{l}\sigma \left(e_{2m\left(k\right)},e_{2n\left(k\right)}\right)\\ +\sigma \left(e_{2n\left(k\right)+1},e_{2m\left(k\right)-1}\right)\end{array}\right\},\frac{1}{2}\left\{\begin{array}{l}\sigma \left(e_{2n\left(k\right)},e_{2m\left(k\right)-1}\right)\\ +\sigma \left(e_{2n\left(k\right)+1},e_{2n}\left(k\right)\right)\end{array}\right\}\right)}\mathrm{\eta (y)dy}}\end{array}$

Now in above inequality if we take $k\to \infty$ and by using results of (15), (20) & (21) we get

${\displaystyle {\int }_0^{{\varphi }_1(\in )}\eta \left(y\right)\text{d}y}\le {\displaystyle {\int }_0^{{\psi }_1\left(\in ,0,0,\in ,\frac{1}{2}\in \right)}\eta \left(y\right)\text{d}y}-{\displaystyle {\int }_0^{{\psi }_2\left(\in ,0,0,\in ,\frac{1}{2}\in \right)}\eta \left(y\right)\text{d}y}.$

Then ${\varphi }_1(\in )\le {\psi }_1\left(\in ,0,0,\in ,\frac{1}{2}\in \right)-{\psi }_2\left(\in ,0,0,\in ,\frac{1}{2}\in \right)={\varphi }_1(\in ).$

This is due to monotone increasing fact of ${\psi }_1$ in its variable and by using property of ${\psi }_2$ that ${\psi }_2\left(y_1,y_2,y_3,y_4,y_5\right)=0,$ if and only if $y_1=y_2=y_3=y_4=y_5=0$ .

From the above inequality we get a contradiction. So that $\in =0$ . This establishes convergent sequence in $\left(E,\sigma \right)$ .

Let $e_n\to z$ as $n\to \infty$ . (24)

Substituting $c=e_{2n},$ $d=z$ in (8) for all $n=1,2,3,\cdots$

$\begin{array}{l}{\displaystyle {\int }_0^{{\varphi }_1\left(\sigma \left(e_{2n+1},Vz\right)\right)}\eta \left(y\right)\text{d}y}\\ \le {\displaystyle {\int }_0^{{\psi }_1\left(\sigma \left(e_{2n},z\right),\sigma \left(e_{2n+1},e_{2n}\right),\sigma \left(Vz,z\right),\frac{1}{2}\left\{\sigma \left(Vz,e_{2n}\right)+\sigma \left(e_{2n+1},z\right)\right\},\frac{1}{2}\left\{\sigma \left(e_{2n},z\right)+\sigma \left(e_{2n+1},e_{2n}\right)\right\}\right)}\eta \left(y\right)\text{d}y}\\ -{\displaystyle {\int }_0^{{\psi }_2\left(\sigma \left(e_{2n},z\right),\sigma \left(e_{2n+1},e_{2n}\right),\sigma \left(Vz,z\right),\frac{1}{2}\left\{\sigma \left(Vz,e_{2n}\right)+\sigma \left(e_{2n+1},z\right)\right\},\frac{1}{2}\left\{\sigma \left(e_{2n},z\right)+\sigma \left(e_{2n+1},e_{2n}\right)\right\}\right)}\eta \left(y\right)\text{d}y}\end{array}$

Taking limit n tends to infinity in the above inequality and using continuity of ${\psi }_1$ and ${\psi }_2$ and Equations (15), (22) we get

$\begin{array}{l}{\displaystyle {\int }_0^{{\varphi }_1\left(\sigma (z,Vz)\right)}\eta \left(y\right)\text{d}y}\\ \le {\displaystyle {\int }_0^{{\psi }_1\left(\sigma \left(z,z\right),\sigma \left(z,z\right),\sigma \left(Vz,z\right),\frac{1}{2}\left\{\sigma \left(Vz,z\right)\right\},0\right)}\eta \left(y\right)\text{d}y}-{\displaystyle {\int }_0^{{\psi }_2\left(\sigma \left(z,z\right),\sigma \left(z,z\right),\sigma \left(Vz,z\right),\frac{1}{2}\left\{\sigma \left(Vz,z\right)\right\},0\right)}\eta \left(y\right)\text{d}y}\\ \le {\displaystyle {\int }_0^{{\psi }_1\left(0,0,\sigma \left(Vz,z\right),\frac{1}{2}\left\{\sigma \left(Vz,z\right)\right\},0\right)}\eta \left(y\right)\text{d}y}-{\displaystyle {\int }_0^{{\psi }_2\left(0,0,\sigma \left(Vz,z\right),\frac{1}{2}\left\{\sigma \left(Vz,z\right)\right\},0\right)}\eta \left(y\right)\text{d}y}\end{array}$

If $\left(Vz,z\right)\ne 0$ then monotone increasing ${\psi }_1$ and ${\psi }_2$ are monotone increasing and ${\psi }_2\left(y_1,y_2,y_3,y_4,y_5\right)=0,$ if and only if $y_1=y_2=y_3=y_4=y_5=0$ , we obtain

${\displaystyle {\int }_0^{{\varphi }_1\left(\sigma (z,Vz\right)}\eta \left(y\right)\text{d}y}\le {\displaystyle {\int }_0^{{\varphi }_1\left(\sigma (z,Vz\right)}\eta \left(y\right)\text{d}y}.$

This contradiction, hence we obtain $\left(Vz,z\right)=0.$ (25)

In similar way we prove that $z=Uz.$ Hence $z=Uz=Vz.$ (26)

Hence (25) & (26) shows that z is a common fixed point of U and V.

Theorem 2.2: Let $\left(E,\sigma \right)$ be a complete metric space and p, q, U and V be four mappings from E to itself such that

$\begin{array}{l}{\displaystyle {\int }_0^{{\varphi }_1\left(\sigma \left(ps,qt\right)\right)}\eta \left(y\right)\text{d}y}\\ \le {\displaystyle {\int }_0^{{\psi }_1\left(\sigma \left(Us,Vt\right),\sigma \left(Us,qt\right),\sigma \left(ps,Vt\right),\sigma \left(Us,ps\right),\sigma \left(Vt,qt\right),\frac{1}{2}\left\{\sigma \left(qt,Us\right)+\sigma \left(ps,Vt\right)\right\},\frac{1}{2}\left\{\sigma \left(Us,Vt\right)+\sigma \left(ps,Us\right)\right\}\right)}\eta \left(y\right)\text{d}y}\\ -{\displaystyle {\int }_0^{{\psi }_2\left(\sigma \left(Us,Vt\right),\sigma \left(Us,qt\right),\sigma \left(ps,Vt\right),\sigma \left(Us,ps\right),\sigma \left(Vt,qt\right),\frac{1}{2}\left\{\sigma \left(qt,Us\right)+\sigma \left(ps,Vt\right)\right\},\frac{1}{2}\left\{\sigma \left(Us,Vt\right)+\sigma \left(ps,Us\right)\right\}\right)}\eta \left(y\right)\text{d}y},\end{array}$ (27)

for all $s,t\in E$ , where ${\psi }_1,{\psi }_2\in {\Psi }_7$ , ${\varphi }_1=\psi \left(e,e,e,e,e,e,e\right)$ , for $e\in \left[0,\infty \right)$ .

i: One of the four mappings p, q, U and V is continuous.

ii: (p, U) & (q, V) are sub compatible.

iii: The pairs $p\left(s\right)\subseteq V\left(s\right)$ and $q\left(s\right)\subseteq U\left(s\right)$ .

iv: Where $\eta :R^{+}\to R^{+}$ is Lebesgue-integrable mappings, which is sum able, non negative and such that for each $\in >0,{\displaystyle {\int }_0^{\in }\eta (y)dy>0}$ .

Then p, q, U and V have a unique common fixed point in E.

Proof: Consider arbitrary point $e_0\in E$ , we construct the sequence $\left\{e_n\right\}$ and $\left\{w_n\right\}$ in E such that

$p{e}_{2n}=V{e}_{2n+1}=w_{2n}$ and $q{e}_{2n+1}=U{e}_{2n+2}=w_{n+1}$ , $n=0,1,2,\cdots$

Let $r_n=\sigma \left(w_n,w_{n+1}\right)$ , Substitution $s=e_{2n}$ and $t=e_{2n+1}$ in (27) we have

$\begin{array}{l}{\displaystyle {\int }_0^{{\varphi }_1\left(\sigma \left(p{e}_{2n},q{e}_{2n+1}\right)\right)}\eta \left(y\right)\text{d}y}={\displaystyle {\int }_0^{{\varphi }_1\left(\sigma \left(e_{2n+1},e_{2n+2}\right)\right)}\eta \left(y\right)\text{d}y}\\ \le {\displaystyle {\int }_0^{\begin{array}{l}{\psi }_1(\sigma \left(U{e}_{2n},V{e}_{2n+1}\right),\sigma \left(U{e}_{2n},q{e}_{2n+1}\right),\sigma \left(p{e}_{2n+1},V{e}_{2n+1}\right),\sigma \left(U{e}_{2n},p{e}_{2n}\right),\sigma \left(V{e}_{2n+1},q{e}_{2n+1}\right),\\ \frac{1}{2}\left\{\sigma \left(q{e}_{2n+1},U{e}_{2n}\right)+\sigma \left(p{e}_{2n},V{e}_{2n+1}\right)\right\},\frac{1}{2}\left\{\sigma \left(U{e}_{2n},V{e}_{2n+1}\right)+\sigma \left(p{e}_{2n},U{e}_{2n}\right)\right\})\end{array}}\eta \left(y\right)\text{d}y}\\ -{\displaystyle {\int }_0^{\begin{array}{l}{\psi }_2(\sigma \left(U{e}_{2n},V{e}_{2n+1}\right),\sigma \left(U{e}_{2n},q{e}_{2n+1}\right),\sigma \left(p{e}_{2n+1},V{e}_{2n+1}\right),\sigma \left(U{e}_{2n},p{e}_{2n}\right),\sigma \left(V{e}_{2n+1},q{e}_{2n+1}\right),\\ \frac{1}{2}\left\{\sigma \left(q{e}_{2n+1},U{e}_{2n}\right)+\sigma \left(p{e}_{2n},V{e}_{2n+1}\right)\right\},\frac{1}{2}\left\{\sigma \left(U{e}_{2n},V{e}_{2n+1}\right)+\sigma \left(p{e}_{2n},U{e}_{2n}\right)\right\})\end{array}}\eta \left(y\right)\text{d}y}\end{array}$

$\begin{array}{l}{\displaystyle {\int }_0^{\varphi \left(\sigma \left(w_{2n},w_{2n+1}\right)\right)}\eta \left(y\right)\text{d}y}\\ \le {\displaystyle {\int }_0^{\begin{array}{l}{\psi }_1(\sigma \left(w_{2n-1},w_{2n}\right),\sigma \left(w_{2n-1},w_{2n+1}\right),\sigma \left(w_{2n+1},w_{2n}\right),\sigma \left(w_{2n-1},w_{2n}\right),\sigma \left(w_{2n},w_{2n+1}\right),\\ \frac{1}{2}\left\{\sigma \left(w_{2n+1},w_{2n}\right)+\sigma \left(w_{2n},w_{2n}\right)\right\},\frac{1}{2}\sigma \left(w_{2n-1},w_{2n}\right)+\sigma \left(w_{2n},w_{2n-1}\right))\end{array}}\eta \left(y\right)\text{d}y}\\ -{\displaystyle {\int }_0^{\begin{array}{l}{\psi }_2(\sigma \left(w_{2n-1},w_{2n}\right),\sigma \left(w_{2n-1},w_{2n+1}\right),\sigma \left(w_{2n+1},w_{2n}\right),\sigma \left(w_{2n-1},w_{2n}\right),\sigma \left(w_{2n},w_{2n+1}\right),\\ \frac{1}{2}\left\{\sigma \left(w_{2n+1},w_{2n}\right)+\sigma \left(w_{2n},w_{2n}\right)\right\},\frac{1}{2}\sigma \left(w_{2n-1},w_{2n}\right)+\sigma \left(w_{2n},w_{2n-1}\right))\end{array}}\eta \left(y\right)\text{d}y}\end{array}$

$\begin{array}{c}{\displaystyle {\int }_0^{{\varphi }_1\left(r_{2n}\right)}\eta \left(y\right)\text{d}y}\le {\displaystyle {\int }_0^{{\psi }_1\left(r_{2n-1},r_{2n-1}+r_{2n},r_{2n,}{r}_{2n-1},r_{2n},\frac{1}{2}\left\{r_{2n}\right\},\frac{1}{2}\left\{r_{2n-1}+r_{2n-1}\right\}\right)}\eta \left(y\right)\text{d}y}\\ -{\displaystyle {\int }_0^{{\psi }_2\left(r_{2n-1},r_{2n-1}+r_{2n},r_{2n,}{r}_{2n-1},r_{2n},\frac{1}{2}\left\{r_{2n}\right\},\frac{1}{2}\left\{r_{2n-1}+r_{2n-1}\right\}\right)}\eta \left(y\right)\text{d}y}\end{array}$

If $r_{2n+1}\le r_{2n}$ then $r_{2n+1}+r_{2n}\le 2r_{2n}$ and

$\begin{array}{c}{\displaystyle {\int }_0^{{\varphi }_1\left(r_{2n}\right)}\eta \left(y\right)\text{d}y}\le {\displaystyle {\int }_0^{{\psi }_1\left(r_{2n-1},2r_{2n},r_{2n,}{r}_{2n-1},r_{2n},\frac{1}{2}\left\{r_{2n}\right\},r_{2n-1}\right)}\eta \left(y\right)\text{d}y}\\ -{\displaystyle {\int }_0^{{\psi }_2\left(r_{2n-1},2r_{2n},r_{2n,}{r}_{2n-1},r_{2n},\frac{1}{2}\left\{r_{2n}\right\},r_{2n-1}\right)}\eta \left(y\right)\text{d}y}\\ <{\displaystyle {\int }_0^{{\varphi }_1\left(r_{2n}\right)}\eta \left(y\right)\text{d}y}.\end{array}$ (28)

Thus we arrive at a contradiction. Hence $r_{2n}\le r_{2n-1}$ , similarly by substituting $s=r_{2n+2},t=r_{2n+1}$ in (27) we can prove that, $r_{2n+1}\le r_{2n}$ , for $n=0,1,2,\cdots$ . Thus $r_{n+1}\le r_n$ , for $n=0,1,2,\cdots$ . Hence the sequence $\left\{r_n\right\}$ is sequence of positive real numbers, which is decreasing and converges to $r\in R$ .

Let $m=\underset{n\to \infty }{\lim }\frac{1}{2}d\left(w_n,w_{n+2}\right)$ . Taking $n\to \infty$ in (27) we have

$\begin{array}{c}{\displaystyle {\int }_0^{{\varphi }_1\left(r_{2n}\right)}\eta \left(y\right)\text{d}y}\le {\displaystyle {\int }_0^{{\psi }_1\left(r,r,r,r,r,r,r\right)}\eta \left(y\right)\text{d}y}-{\displaystyle {\int }_0^{{\psi }_2\left(r,r,r,r,r,r,m\right)}\eta \left(y\right)\text{d}y}\\ \le {\displaystyle {\int }_0^{{\varphi }_1\left(r\right)}\eta \left(y\right)\text{d}y}-{\displaystyle {\int }_0^{{\psi }_2\left(r,r,r,r,r,r,m\right)}\eta \left(y\right)\text{d}y}.\end{array}$